Answer:
It is given in the question that molarity of the sulphuric acid is 2M, the volume of the sulphuric acid is 20 mL, the volume of the solution is 1`L.
Answer:
A. It's a 'clean' energy. Your cooch need a cleanup
It is possible to rate your active reading skills either by using a number is a specific rate or by using a word that qualifies your performance.
<h3>What are active reading skills?</h3>
Active reading skills are a set of skills that help you read actively; this means skills to effectively read a text and understand it.
<h3>How to rate your reading skills?</h3>
In this case, you are asked to rate your ability to pay attention to your understanding, thoughts, and questions while reading. To do this you can:
Rate using numbers:
- Select a specific scale rating such as 1 to 5 or 1 10.
- Analyze honestly if you used this ability while reading the text.
- Give yourself a number. For example, if you apply this skill only sometimes while reading you can rate yourself 5 out of 10.
Rate using words:
- Select the types of words that you will use, the most common ones are frequency words such as always, sometimes, and never.
- Analyze honestly your performance.
- Find the word that best fits it.
Learn more about rate in: brainly.com/question/2278897
Answer:
C₆H₈O₆
Explanation:
The molecular formula of given compound is C₆H₈O₆. Because there are six carbon, six oxygen and eight hydrogen atom present in this compound.
The molecular weight of following compound is,
C₆H₈O₆
C = 12 amu
H = 1 amu
O = 16 amu
C₆H₈O₆ = 12×6 + 1×8 + 16×6
C₆H₈O₆ = 72 +8 + 96
C₆H₈O₆ = 176 g/mol
Answer:
0.0907 M
Explanation:
Before you can calculate the molarity, you need to convert grams to moles (via molar mass) and convert mL to L.
(Step 1)
Molar Mass (C₈H₅O₄K):
8(12.011 g/mol) + 5(1.008 g/mol) + 4(15.998 g/mol) + 39.098 g/mol
Molar Mass (C₈H₅O₄K): 204.218 g/mol
0.6013 g C₈H₅O₄K 1 mole
------------------------------ x ------------------ = 0.00294 moles C₈H₅O₄K
204.218 g
(Step 2)
1,000 mL = 1 L
32.47 mL 1 L
--------------- x ----------------- = 0.03247 L
1,000 mL
(Step 3)
Molarity (M) = moles / volume (L)
Molarity = 0.00294 moles / 0.03247 L
Molarity = 0.0907 M
