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Alinara [238K]
3 years ago
6

Double-click on a sheet tab to _______ the sheet.

Chemistry
2 answers:
Vika [28.1K]3 years ago
7 0
Copy it I think hp[e that is right lol
Lostsunrise [7]3 years ago
7 0
/////To open////so it is to open a page on a laptop and phone and others.
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1
fredd [130]
Answer: Combustion changes the potential chemical energy into kinetic energy in the form of heat. For combustion an organic wood combines with oxygen already in the air and undergoes a chemical reaction that gives off carbon dioxide,water,and energy in the form of heat and light.
8 0
3 years ago
What must be true of a substance with a lot
LUCKY_DIMON [66]

Answer:

A is the answer.

Explanation:

8 0
3 years ago
Read 2 more answers
What volume of a 3.0 M stock solution of H2SO4 is needed to prepare 2.8 L of a 1.6 M H2SO4 solution?
Georgia [21]
Use M1V1 = M2V2 to solve
3(V1) = 2.8 * 1.6
3(V1) = 4.48
V1 = 1.493 L of stock solution
4 0
3 years ago
Read 2 more answers
Consider a situation in which 211 g
Stella [2.4K]

Answer:

3.00 mol

Explanation:

Given data:

Mass of P₄ = 211 g

Mass of oxygen = 240 g

Moles of P₂O₅ = ?

Solution:

Chemical equation:

P₄ + 5O₂       →     2P₂O₅

Number of moles of P₄:

Number of moles = mass/ molar mass

Number of moles = 211 g / 123.88 g/mol

Number of moles = 1.7 mol

Number of moles of O₂ :

Number of moles = mass/ molar mass

Number of moles = 240 g / 32g/mol

Number of moles = 7.5 mol

Now we will compare the moles of product with reactant.

                       O₂         :         P₂O₅

                        5          :           2

                        7.5       :        2/5×7.5 = 3.00

                       P₄          :         P₂O₅

                        1           :           2

                       1.7         :       2×1.7 = 3.4 mol

Oxygen is limiting reactant so the number of moles of P₂O₅ are 3.00 mol.

Mass of P₂O₅:

Mass = number of moles × molar mass

Mass = 3 mol ×283.9 g/mol

Mass = 852 g

3 0
3 years ago
How to calculate work done with change in volume and pressure.
natali 33 [55]

W = \displaystyle \int dW  = \displaystyle \int^{V_2}_{V_1}  p ~dV = p(V_2 - V_1) = p \Delta V

3 0
2 years ago
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