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3 years ago

Which is not a family of the periodic table?

Physics

2 answers:

GalinKa [24]3 years ago

8 0

Answer

Anion The electronic configuration of many ions is that of the closest noble gas to them in the periodic table.

Explanation

Alkaline-earth metal, any of the six chemical elements that comprise Group 2 (IIa) of the periodic table.

Noble gas, any of the seven chemical elements that make up Group 18 (VIIIa)

Halogens The halogens, members of Group 17 of the periodic table, include the elements

Mark me as brainleist pls

Vsevolod [243]3 years ago

6 0

Answer:

anions

Explanation:

The other are families of the periodic table.

An anion is a negatively charged ion.

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A natural water molecule (H2O) in its vapor state has an electric dipole moment of magnitude, p = 6.2 x 10-30 C.m. (a) Find the

Vika [28.1K]

Answer:

a $D = 3.9 *10^{-12} \ m$

b $\tau_{max} = 1.24 *10^{-25} \ N\cdot m$

c $W = 2.48 *10^{-25} J$

Explanation:

From the question we are told that

The magnitude of electric dipole moment is $\sigma = 6.2 *10^{-30} \ C \cdot m$

The electric field is $E = 2*10^{4} \ N/C$

The distance between the positive and negative charge center is mathematically evaluated as

$D = \frac{\sigma }{10 e}$

Where e is the charge on one electron which has a constant value of $e = 1.60 *10^{-19} \ C$

Substituting values

$D = \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}$

$D = 3.9 *10^{-12} \ m$

The maximum torque is mathematically represented as

$\tau_{max} = \sigma * E * sin (\theta)$

Here $\theta = 90^o$

This because at maximum the molecule is perpendicular to the field

substituting values

$\tau_{max} = 6.2 *10^{-30} * 2*10^{4} sin ( 90)$

$\tau_{max} = 1.24 *10^{-25} \ N\cdot m$

The workdone is mathematically represented as

$W = V_{(180)} - V_{0}$

where $V_{(180)}$ is the potential energy at 180° which is mathematically evaluated as

$V_{(180) } = - \sigma * E cos (180)$

Where the negative signifies that it is acting against the field

substituting values

$V_{(180) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (180)$

$V_{(180) } = 1.24*10^{-25} J$

and

$V_{(0)}$ is the potential energy at 0° which is mathematically evaluated as

$V_{(0) } = - \sigma * E cos (0)$

substituting values

$V_{(0) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (0)$

$V_{(0) } =- 1.24*10^{-25} J$

So $W = 1.24 *10^{-25} - [-1.24 *10^{-25}]$

$W = 2.48 *10^{-25} J$

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4 years ago

What will happen to a periodic wave acted upon an external damping force?

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If you press as hard as you can against a brick wall until you begin to sweating and breathing hard did you do any work on the w

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