Answer:1.81
(a) Explanation:the turn ratio= input voltage÷output voltage.
400÷220=1.81.
Don't know how to solve b part...
Answer:
0.88752 kgm²
0.02236 Nm
Explanation:
m = Mass of ball = 1.2 kg
L = Length of rod = 0.86 m
= Angle = 90°
Rotational inertia is given by

The rotational inertia is 0.88752 kgm²
Torque is given by

The torque is 0.02236 Nm
To find the temperature it is necessary to use the expression and concepts related to the ideal gas law.
Mathematically it can be defined as

Where
P = Pressure
V = Volume
n = Number of moles
R = Gas constant
T = Temperature
When the number of moles and volume is constant then the expression can be written as

Or in practical terms for this exercise depending on the final temperature:

Our values are given as

Replacing

Therefore the final temperature of the gas is 800K