Answer:
2100g or 2.1kg
Explanation:
Based on the equation given,
One mole of Fe2O3 gives two moles of Fe
Molar mass for Fe2O3 is 160g/mol
Molar mass for two Fe is 112g/mol
Convert 3kg to gram
3×1000=3000grams
160g of Fe2O3-112 g of Fe
3000g of Fe2O3-xg of Fe
Xg=3000×112/160
Xg=2100g
To convert to kg
2100/1000=2.1kg
Mass of Fe is 2.1kg
The reaction, Fe2O3 + 3CO------> 2Fe + 3CO2 is an oxidation-reduction reaction.
An oxidation-reduction reaction is a reaction in which there is a change in oxidation number from left to right in the reaction. This is because, a specie is oxidized and another specie is reduced.
In the reaction; Fe2O3 + 3CO------> 2Fe + 3CO2, we can see that the oxidation number of iron decreased from +3 on the left hand side to zero on the right hand side. The oxidation number of carbon was increased from + 2 to +4.
Learn more: brainly.com/question/10079361
Central "carbon" atom
2 oxygen atoms
held together by "covalent" bonds
has a "1s2 2s2 2px1 2py1 2pz0" electron
geometry
carbon atom is "sp" hybridized
<u>Answer:</u>
<em>0.264 g of
can be formed from 288 mg of
</em>
<u>Explanation:</u>
The balanced chemical equation is

The conversions are
Mass in mg
is converted to mass in g
Mass in g
is converted to moles
by dividing with molar mass
Moles
is converted to moles
by using the mole ratio of
is 9 : 6
Moles
is converted to mass
by multiplying with molar mass 
mass in mg
> mass in g
>moles
> moles
> mass 

=0.264g (Answer)
Answer:

Explanation:
You look at the type of atom and their electronegativity difference.
If ΔEN <1.6, covalent; if ΔEN >1.6, ionic
Ar/Xe: Noble gases; no reaction
F/Cs: Non-metal + metal; ΔEN = |3.98 – 0.79| = 3.19; Ionic
N/Br: Two nonmetals; ΔEN = |3.04 - 2.98| = 0.