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nadezda [96]
3 years ago
8

How can I solve this sequence problem?​

Engineering
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

Podes  hablar en español?

Explanation:

dlinn [17]3 years ago
5 0
I can’t read it man, I’m sorry.. comment on this I will help you as much as I can
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4 0
3 years ago
A book of the Law was found in the Temple, which was being repaired, during the___
grigory [225]

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Explanation:

5 0
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Read 2 more answers
Type the correct answer in the box. Spell all words correctly.
Alik [6]

Answer:

management engineer

Explanation:

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8 0
3 years ago
Write a loop to print all elements in hourly_temperature. Separate elements with a -> surrounded by spaces. Sample output for
ELEN [110]

The answer & explanation for this question is given in the attachment below.

6 0
3 years ago
Your program must output each student’s name in the form: last name followed by a comma, followed by a space, followed by the fi
Reptile [31]

Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

  string studentFName;

  string studentLName;

  int testScore;

  char grade;

};

void readStudentData(StudentType students[]){

  int i = 0;

 

  ifstream infile;

  infile.open("inputStudentData.txt");

 

 

  while (!infile.eof())

  {

   infile >> students[i].studentFName;

   infile >> students[i].studentLName;

   infile >> students[i].testScore;

   students[i].grade = getStudentGrade(students[i].testScore);

      i++;

  }

}

char getStudentGrade(int testScore){

  char grade;

  if(testScore >= 80) {

      grade = 'A';      

  }

  else if(testScore >= 60) {

      grade = 'B';

  }

  else if(testScore >= 50) {

      grade = 'C';  

  }

  else if(testScore >= 40) {

      grade = 'D';      

  }

  else {

      grade = 'F';  

  }

  return grade;

}

int main()

{

 

  StudentType students[10];

 

  readStudentData(students);

 

  for(int i=0;i<maxStudents;i++) {

      students[i].grade = getStudentGrade(students[i].testScore);

  }

 

  for(int i=0; i<maxStudents; i++){    

      cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  ofstream outputFile;

  outputFile.open ("outputStudentData.txt");

 

  for(int i=0; i<maxStudents; i++){    

      outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

  }

  outputFile.close();

  return 0;

}

3 0
3 years ago
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