Given :
Force,
.
Force is acting at point A( 2 m, 3 m ) and B( 3 m, 5 m )
To Find :
The work done by force F .
Solution :
Displacement vector between point A and B is :
![\vec{d} = (3-2)\hat{i} + (5-3)\hat{j}\\\\\vec{d} = \hat{i} + 2\hat{j}](https://tex.z-dn.net/?f=%5Cvec%7Bd%7D%20%3D%20%283-2%29%5Chat%7Bi%7D%20%2B%20%285-3%29%5Chat%7Bj%7D%5C%5C%5C%5C%5Cvec%7Bd%7D%20%3D%20%5Chat%7Bi%7D%20%2B%202%5Chat%7Bj%7D)
Now, we know work done is given by :
![W = \vec{F}.\vec{d}\\\\W= (2\hat{i} + 5\hat{j}).(\hat{i}+\hat{2j})\\\\W = (2\times 1) +( 5\times 2) \ kJ\\\\W = 12 \ kJ](https://tex.z-dn.net/?f=W%20%3D%20%5Cvec%7BF%7D.%5Cvec%7Bd%7D%5C%5C%5C%5CW%3D%20%282%5Chat%7Bi%7D%20%2B%205%5Chat%7Bj%7D%29.%28%5Chat%7Bi%7D%2B%5Chat%7B2j%7D%29%5C%5C%5C%5CW%20%3D%20%282%5Ctimes%201%29%20%2B%28%205%5Ctimes%202%29%20%5C%20kJ%5C%5C%5C%5CW%20%3D%2012%20%5C%20kJ)
W = 12000 J
Therefore, work done by force is 12000 J .
Answer:
modulus =3.97X10^6 Ib/in^2, Poisson's ratio = 0.048
Explanation:
Modulus is the ratio of tensile stress to tensile strain
Poisson's ratio is the ratio of transverse contraction strain to longitudinal extension strain within the direction of the stretching force
And contraction occur from 0.6 in x 0.6 in to 0.599 in x 0.599 in while 2 in extended to 2.007, with extension of 0.007 in
A spud wrench and pipe is for install pipes
Answer:
Information such as tolerance and scale can be found in the <u>title block</u> of an engineering drawing
Explanation:
The title block of an engineering drawing can normally be found on the lower right and corner of an engineering drawing and it carries the information that are used to specify details that are specific the drawing including, the name of the project, the name of the designer, the name of the client, the sheet number, the drawing tolerance, the scale, the issue date, and other relevant information, required to link the drawing with the actual structure or item