Answer:
What is the correct path of sperm cells through the male reproductive system?
Epididymis, seminiferous tubules, urethra, vas deferens
<u>Seminiferous tubules, epididymis, vas deferens, urethra
</u>
Urethra, seminiferous tubules, epididymis, vas deferens
Seminiferous tubules, vas deferens, epididymis, urethra
Hope this helps :)
Have a great day !
5INGH
Explanation:
Answer:
a)![\lambda=6.63\times10^{-31}m](https://tex.z-dn.net/?f=%5Clambda%3D6.63%5Ctimes10%5E%7B-31%7Dm%20)
b)![\lambda=6.63\times10^{-39}m](https://tex.z-dn.net/?f=%5Clambda%3D6.63%5Ctimes10%5E%7B-39%7Dm%20)
c)![\lambda=9.97\times10^{-11}m](https://tex.z-dn.net/?f=%5Clambda%3D9.97%5Ctimes10%5E%7B-11%7Dm%20)
d)
m
e)λ=∞
Explanation:
De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:
![\lambda=\frac{h}{P}=\frac{h}{mv}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bh%7D%7BP%7D%3D%5Cfrac%7Bh%7D%7Bmv%7D%20)
with h the Plank's constant (
) and P the momentum of the object that is mass (m) times velocity (v).
a)![\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}kg*1.0)}](https://tex.z-dn.net/?f=%20%5Clambda%3D%5Cfrac%7B6.63%5Ctimes10%5E%7B-34%7D%7D%7B%281.0%5Ctimes10%5E%7B-3%7Dkg%2A1.0%29%7D)
![\lambda=6.63\times10^{-31}m](https://tex.z-dn.net/?f=%5Clambda%3D6.63%5Ctimes10%5E%7B-31%7Dm%20)
b)![\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}*(1.00\times10^{8}))}](https://tex.z-dn.net/?f=%20%5Clambda%3D%5Cfrac%7B6.63%5Ctimes10%5E%7B-34%7D%7D%7B%281.0%5Ctimes10%5E%7B-3%7D%2A%281.00%5Ctimes10%5E%7B8%7D%29%29%7D)
![\lambda=6.63\times10^{-39}m](https://tex.z-dn.net/?f=%5Clambda%3D6.63%5Ctimes10%5E%7B-39%7Dm%20)
c)![\lambda=\frac{6.63\times10^{-34}}{(6.65\times10^{-27}*1000)}](https://tex.z-dn.net/?f=%20%5Clambda%3D%5Cfrac%7B6.63%5Ctimes10%5E%7B-34%7D%7D%7B%286.65%5Ctimes10%5E%7B-27%7D%2A1000%29%7D)
![\lambda=9.97\times10^{-11}m](https://tex.z-dn.net/?f=%5Clambda%3D9.97%5Ctimes10%5E%7B-11%7Dm%20)
d)![\lambda=\frac{6.63\times10^{-34}}{(74*2.22)}](https://tex.z-dn.net/?f=%20%5Clambda%3D%5Cfrac%7B6.63%5Ctimes10%5E%7B-34%7D%7D%7B%2874%2A2.22%29%7D)
m
e) ![\lambda=\frac{6.63\times10^{-34}}{(74*0)}](https://tex.z-dn.net/?f=%20%5Clambda%3D%5Cfrac%7B6.63%5Ctimes10%5E%7B-34%7D%7D%7B%2874%2A0%29%7D)
λ=∞
Answer:
60 boxes
Explanation:
The work done by lifting a single box is equal to the force applied (the weight of the box) times the displacement of the box:
![W_1 = Fd=(12.0 N)(5.00 m)=60 J](https://tex.z-dn.net/?f=W_1%20%3D%20Fd%3D%2812.0%20N%29%285.00%20m%29%3D60%20J)
Power is related to the work done by the equation:
![P=\frac{W}{t}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7Bt%7D)
where W is the work done and t is the time. In this problem, we are told that the power used is P=60.0 W, while the time taken is t = 1 min = 60 s, so the total work done must be
![W=Pt=(60.0 W)(60 s)=3600 J](https://tex.z-dn.net/?f=W%3DPt%3D%2860.0%20W%29%2860%20s%29%3D3600%20J)
Therefore, the number of boxes that she has to lift in order to use this power is the total work divided by the work done in lifting each box:
![N=\frac{W}{W_1}=\frac{3,600 J}{60 J}=60](https://tex.z-dn.net/?f=N%3D%5Cfrac%7BW%7D%7BW_1%7D%3D%5Cfrac%7B3%2C600%20J%7D%7B60%20J%7D%3D60)
Answer:
dolphin= 7 meters/1 second walrus= 5 meters/1 second
Explanation:
56 divided by 8 is 7
30 diviided by 6 is 5