The variables that show a direct relationship are :
- The speed of a car and the distance traveled
- Number of students in a cafeteria and the amount of food consumed
- The distance a planet is from the sun and that planet's temperature
- The mass of a space shuttle and its acceleration through space
In direct relationship, when one factor is increased/decreased , it will directly cause the other factor to be increased/decreased
Answer: Heat transfers through brick walls and glass through conduction. In conduction heat is transferred by vibration of molecules. most energetic molecules vibrate and pass on the energy to less energetic molecules. Then they vibrate and further pass on the energy. In this way heat is transferred out of the home. Heat also transfers through the leakage of warm air from doors and windows. This occurs through convection. In convection energy is transferred through bulk movement of liquid and air molecules. Heat also transfers from insulation. in insulation there is no material in between the layers. So heat transfer through insulation occurs through radiations that occurs by X-Rays, Ultravoilet rays etc.
There’s many terms to it
1 : to keep in a safe or sound state He conserved his inheritance. especially : to avoid wasteful or destructive use of conserve natural resources conserve our wildlife. 2 : to preserve with sugar. 3 : to maintain (a quantity) constant during a process of chemical, physical, or evolutionary change conserved DNA ...
Beats are interference patterns between two tones of different frequencies. To prove the skeptic first, play the recorded audio as there are no beats in it. Now take two sound sources with different frequencies. When both sources are turned on, we hear notes that rise and fall at equal intervals. That's what's called beats.
A frequency beat occurs when two waves with different frequencies overlap, causing alternating cycles of constructive and destructive interference between the waves.
When we tap the table with our finger, then put our ear to the table, and tap the table surface as far as 30 cm from our ear. Then the sound of beats on the table will sound louder when we put our ears on the table. So, it can be concluded that solid objects can conduct sound better than air. This is because the molecules or particles of solid objects are denser than air.
Learn more about the beat's frequency at brainly.com/question/14157895
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Answer:
![v_A=7667m/s\\\\v_B=7487m/s](https://tex.z-dn.net/?f=v_A%3D7667m%2Fs%5C%5C%5C%5Cv_B%3D7487m%2Fs)
Explanation:
The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:
![F_g=\frac{GMm}{R^{2} }](https://tex.z-dn.net/?f=F_g%3D%5Cfrac%7BGMm%7D%7BR%5E%7B2%7D%20%7D)
Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.
Also, we know that the centripetal force of an object describing a circular motion is given by:
![F_c=m\frac{v^{2}}{R}](https://tex.z-dn.net/?f=F_c%3Dm%5Cfrac%7Bv%5E%7B2%7D%7D%7BR%7D)
Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.
Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:
![\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}](https://tex.z-dn.net/?f=%5Cfrac%7BGMm%7D%7BR%5E2%7D%3Dm%5Cfrac%7Bv%5E2%7D%7BR%7D%5C%5C%20%5C%5C%5Cimplies%20v%3D%5Csqrt%7B%5Cfrac%7BGM%7D%7BR%7D%7D)
Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So
and
(Since
). Then, we get:
![v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s](https://tex.z-dn.net/?f=v_A%3D%5Csqrt%7B%5Cfrac%7B%286.67%2A10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%285.97%2A10%5E%7B24%7Dkg%29%7D%7B6.774%2A10%5E6m%7D%20%7D%3D7667m%2Fs%5C%5C%5C%5Cv_B%3D%5Csqrt%7B%5Cfrac%7B%286.67%2A10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%285.97%2A10%5E%7B24%7Dkg%29%7D%7B7.103%2A10%5E6m%7D%20%7D%3D7487m%2Fs)
In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).