All categories

3 years ago

Calculate the vapor pressure of water at T=90°C

Chemistry

1 answer:

LenKa [72]3 years ago

4 0

The equilibrium vapour pressure is typically the pressure exerted by a liquid .... it is A FUNCTION of temperature...

Explanation:

By way of example, chemists and physicists habitually use

saturated vapour pressure

...where

SVP

is the vapour pressure exerted by liquid water. At

100

∘

SVP

⋅

. Why?

Well, because this is the normal boiling point of water: i.e. the conditions of pressure (i.e. here

⋅

) and temperature, here

100

∘

, at which the VAPOUR PRESSURE of the liquid is ONE ATMOSPHERE...and bubbles of vapour form directly in the liquid. As an undergraduate you should commit this definition, or your text definition, to memory...

At lower temperatures, water exerts a much lower vapour pressure...but these should often be used in calculations...especially when a gas is collected by water displacement. Tables of

saturated vapour pressure

are available.

You might be interested in

When mountains are young, like the Rocky Mountains, they are very tall, with sharp jagged shapes. When mountains are old, they

marta [7]

I think A.weathering, is the best possible answer

6 0

3 years ago

Help me please thanks

Evgesh-ka [11]

Then answer would be D. Answer D is correct because you would need to use a better solvent to see the ink separate on the chromatography paper. Hope that helps. :)

6 0

3 years ago

a closed flask of air (0.250 L) contains 5.00 "puffs" of particles. The pressure probe on the flask reads 93 kPa. A student uses

Sergio039 [100]

Answer: New pressure inside the flask would be 148.8 kPa.

Explanation: The combined gas law equation is given by:

$PV=nRT$

As the flask is a closed flask, so the volume remains constant. Temperature is constant also.

So, the relation between pressure and number of moles becomes

$P=n\\or\\\frac{P}{n}=constant$

$\frac{P_1}{n_1}=\frac{P_2}{n_2}$

Initial conditions:

$P_1=93kPa\\n_1=5\text{ puffs}$

Final conditions: When additional 3 puffs of air is added

$P_2=?kPa\\n_2=8\text{ puffs}$

Putting the values, in above equation, we get

$\frac{93}{5}=\frac{P_2}{8}\\P_2=148.8kPa$

3 0

3 years ago

What are examples of smaller bodies

Inga [223]

comets, astroids oort clouds which surround the kuiper belt

8 0

3 years ago

Adding/ removing

masya89 [10]

Answer:

False- The number of electrons does not affect the type of element.

Explanation:

The adding/removing of protons is what changes the type of element. for example, if you have a molecule of Boron, which has 5 protons, and you add one proton, you will have created a carbon molecule with 6 protons. The number of protons of an element is its atomic number. Elements can have varying numbers of both electrons and neutrons without changing the type of element.

3 0

3 years ago