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Galina-37 [17]
3 years ago
15

In the equation, 2Al (s) + 3Cl2 (g) → 2AlCl3 (s), the large number “3” in front of the Cl2 indicates:

Chemistry
2 answers:
Sophie [7]3 years ago
6 0

<u>Answer:</u> The correct answer is the number of moles of chlorine molecules needed to balance the equation.

<u>Explanation:</u>

A balanced chemical equation follows law of conservation of mass.

This law states that mass on either side of the reaction remains constant. Also, mass can neither be created, nor be destroyed, but it can only be transformed from one form to another form.

In the given chemical equation:

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

The numbers '2', '3' and '2' represents the number of moles of the specie required to balance a chemical equation.

Here, Cl_2 is a molecule of 2 chlorine atoms.

Hence, the correct answer is the number of moles of chlorine molecules needed to balance the equation.

dybincka [34]3 years ago
5 0

In the equation,

2Al(s) + 3Cl2(g) —> 2AlCl3(s),

the large number "3" in front of Cl2 indicates the the number of moles of Chlorine molecules needed to balance the equation.

Hope this will help you. 

If you like my answer. Please mark it as brainliest  And  Be my follower if possible.

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450g of chromium (III) sulfate reacts with excess potassium phosphate. How many grams of potassium sulfate will be produced? (AN
Oduvanchick [21]

Answer:

599.26 grams of potassium sulfate will be produced.

Explanation:

Cr_2(SO_4)_3(aq)+2K_3PO_4(aq)\rightarrow 2CrPO_4(s)+3K_2SO_4(aq)

Moles of chromium (III) sulfate = \frac{450 g}{392 g/mol}=1.1480 mol

According to reaction, 1 mole of chromium (III) sulfate gives 3 moles of potassium sulfate.

Then 1.1480 moles of chromium (III) sulfate will give:

\frac{3}{1}\times 1.1480 mol=3.4440 mol

Mass of 3.4440 moles of potassium sulfate:

= 3.4440 mol × 174 g/mol = 599.26 g

599.26 grams of potassium sulfate will be produced.

8 0
3 years ago
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svp [43]

Answer:

A

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Explanation:

4 0
3 years ago
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6 0
3 years ago
Which of the following electron transitions in a hydrogen atom emits light of the shortest wavelength? Circle the correct answer
Lilit [14]

Answer:

Transition from n = 4 to n = 1  corresponds to shortest wavelength.

Explanation:

         Process                   \mid \Delta n\mid =\mid \frac{1}{(n)_{final}^{2}}-(\frac{1}{n_{initial}^{2}})\mid

             A                                         0.9375

             B                                          0.75

             C                                          0.0421

             D                                          0.1875

According to Rydberg equation for electronic transition in H-like atoms:

           \frac{1}{\lambda }=R_{H}\mid (\frac{1}{n_{final}^{2}}-(\frac{1}{n_{initial}^{2}})\mid

where, \lambda is wavelength of light emitted or absorbed, R_{H} is Rydberg constant.

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4 0
3 years ago
1. Determine the number of atoms in 4.64 g gold.
liubo4ka [24]

Answer:

The answer to your question is below

Explanation:

1.-

a) Look for the mass number of Gold in the periodic table

Mass number = 197 g

Use proportions to answer this question

                          197 g of gold ------------- 6.023 x 10 ²³ atoms

                            4.64 g of gold ----------  x

                            x = (4.64 x 6.023 x 10²³) / 197

                           x = 1.42 x 10²² atoms

2.- mass of 4.12 x 10²⁴ molecules of glucose

Molecular mass = (6 x 12) + (12 X 1) + (6 x 16)

                          = 72 + 12 + 96

                          = 180 g

             180 g of glucose ------------------- 6.023 x 10 ²³ molecules

                x                        -------------------  4.12 x 10 ²⁴ molecules

                x = (4.12 x 10²⁴ x 180) / 6.023 x 10²³

               x = 1231.3 g of glucose                  

4 0
3 years ago
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