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3 years ago

A line passes through the points (0, 2) and (1, 6). What is its equation in slope-intercept form?

Mathematics

1 answer:

olchik [2.2K]3 years ago

4 0

Answer:

y=4x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-2)/(1-0)

m=4/1

m=4

y-y1=m(x-x1)

y-2=4(x-0)

y-2=4x

y=4x+2

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3 years ago

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consider the following equations: -x-y=1 y=x+3 if the two equations are graphed, at what point do the lines representing the two

Oksana_A [137]

Answer:

(-2, 1)

Step-by-step explanation:

consider the following equations: -x-y=1 y=x+3

For the lines to intersect, the values must be the same

-x-y=1

x + y = -1

y = -x - 1

Equating the y values

-x - 1 = x+ 3

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2 years ago

Which equation represents the line that passes through the points (-5,2) and (9,0)

V125BC [204]

Step-by-step explanation:

Given points 

( -5 , 2) and (9 , 0)

First calculating slope(m)

= ( y2 - y1) / ( x2 - x1) 

= ( 0-2) / ( 9+5)

= -2 / 14

= -1/7

Now The equation of line is given by 

y - y1 = m ( x - x1) 

y -2 = -1/7 (x + 5)

7( y - 2) = -1(x + 5)

7y - 14 = -x -5

x + 7y -14 +5 = 0

x + 7y - 9 = 0 

Which is the required equation 

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3 years ago

If f(x)=-2x+2 then find f(1/2)

natima [27]

Answer:

F is 0

Step-by-step explanation:

If you divide X on both sides to get X on one side, it will end with F = -2 + 2, which is 0

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3 years ago