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Savatey [412]
3 years ago
7

Can you please help me?

Physics
2 answers:
Anastasy [175]3 years ago
5 0

Answer:

highest frequency shortest wavelength

Oliga [24]3 years ago
4 0

Answer:

2nd one

Explanation:

highest frequency shortest wavelength

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Katie is walking in an orange grove. She looks at all of the orange trees. She wants to find out how many seeds are in each oran
aliya0001 [1]

Answer:

What she can do to collect the data is;

B. Gather a few oranges and see how many seeds are in each

Explanation:

The quantity Katie wants to find out is the number of seeds contained in each orange

Therefore, the required population = The number of seeds in a given orange

The method of estimation of the number of seeds per orange is sampling method, whereby the number of seeds in each of the orange in the sample is used to as an hypothesis as to the number of seeds expected in each orange of the entire population.

Therefore, in order to collect the data, she can gather a few oranges and see how many seeds are in each.

3 0
3 years ago
What kind of line on a distance vs. time graph indicates that the object is accelerating?
suter [353]

Answer: a curved line

Explanation: a straight line indicates that the object is moving at a constant velocity because it has one slope, but a curved line on a distance-time graph indicates that the velocity is constantly changing because the slope is changing, which is acceleration. the line could be curved in any direction, as long as it shows a change in slope.

7 0
3 years ago
If a star has a parallax of 0.050 arc second, what is its distance in pc? In ly? In AU? Seeds, Michael A.. Universe: Solar Syste
vaieri [72.5K]

Answer:

Distance in pc= 20parsecs

Distance in zLY= 65.2LY

Distance in AU= 4.1×10^6AU

Explanation:

Using the formular:

d = 1/p

Where d = distance

P= parallax angle in arc of second

d= 1/0.050

d= 20 parsed

Converting to Lighy years,LY :

1 PC = 3.26LY

d= 20pc × (3.26Ly/1pc)

d= 65.2Ly

To convert to AU, 206,265 AU = 1pc

d= 20pc × (2.06×10^5AU/1pc)

d= 4.1×10^6AU

5 0
4 years ago
Read 2 more answers
A rocket's acceleration is 6.0 m/s 2 . Assuming it starts at 0 m/s, how long will it take for the rocket to reach a velocity of
kupik [55]
At=v-u, where u=0

t= v/a=42/6 = 7
Answer: 7 seconds
8 0
3 years ago
Tap on the photo. For each diagram, explain why the light behaves in the way that it does.
dem82 [27]

Answer:

Diagram 1, 3 and 4 can be explained with the phenomenon of refraction.

Refraction occurs when a ray of light crosses the interface between two mediums with different optical density: when this occurs, the ray of light is bent and its speed changes, according to Snell's law

n_1 sin \theta_1 = n_2 sin \theta_2

where n_1,n_2 are the refractive index of the 1st and 2nd medium

\theta_1, \theta_2 are the angle that the incident ray and the refracted ray makes with the normal to the interface

In diagram, 1, the ray of light arrives perpendicularly to the interface, so it is refracted through the medium but it doesn't change its direction (only its speed).

In diagram 3, the ray of light is refracted twice: at the 1st interface and at the 2nd interface. In the 1st case, it goes from a medium with lower refractive index to a medium with higher refractive index (n_1), this means that \theta_2, so the ray bends towards the normal. Vice-versa, in the 2nd case the ray goes from a medium with higher refractive index to a medium with lower refractive index (n_1>n_2), so it bends away from the normal (\theta_2>\theta_1).

In diagram 4, the ray of light is also refracted twice. The ray of light here acts exactly the same as in diagram 3, h

However, this time the 2nd interface is the opposite direction with respect to diagram 3, so in this case the ray of light at the 2nd interface bends in the opposite direction (still away from the normal).

Diagram 2 instead is an example of reflection, that occurs when a ray of light bounces off the interface between the two mediums, withouth entering the 2nd medium.

According to the law of reflection:

- The incoming ray, the reflected ray and the normal to the boundary are all in the same plane

- The angle of incidence is equal to the angle of reflection (both are measured relative to the normal to the boundary)

Therefore in this diagram, the ray of light hits the boundary at approx. 45 degrees from the normal, and then it is reflected back approximately at 45 degrees on the other side with respect to the normal.

3 0
4 years ago
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