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Montano1993 [528]
3 years ago
7

What happens to a visible light wave when you increase the frequency

Physics
1 answer:
Anastasy [175]3 years ago
6 0
When frequency increases, the wavelength halves.
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The impulse-momentum theorem

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Explain how a compass works using scientific terminology.
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A compass works by detecting and responding to the Earth's natural magnetic fields. The Earth has an iron core that is part liquid and part solid crystal, due to gravitational pressure. It is believed that movement in the liquid outer core is what produces the Earth's magnetic field.

Explanation:

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A cylinder with moment of inertia I1 rotates with angular speed ω0 about a frictionless vertical axle. A second cylinder, with m
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Answer:

Part(a): The final angular velocity is \omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}

Part(b): The ratio of the rotational energies is \dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})},showing the the energy of th system will decrease.

Explanation:

Part(a):

If 'I' be the moment of inertia of an object and '\omega' be its angular velocity then the angular momentum 'L' of the object can  be written as

L = I \omega

If 'I_{1}' and 'I_{2}' be the moment of inertia of the two cylinders and '\omega_{1}' and '\omega_{2}' be the initial angular velocity of the cylinders and '\omega_{1}{'}' and '\omega_{2}^'}' be their respective final angular velocity, then from conservation of angular momentum,

I_{1} \omega_{1} + I_{2} \omega_{2} = I_{1} \omega_{1}^{'} + I_{2} \omega_{2}^{'}

Given, \omega_{1} = \omega_{i},~\omega_{2} = 0,~\omega_{1}^{'} = \omega_{2}^{'} = \omega_{f}. From the above expression

&& I_{1} \omega_{i} = (I_{1} + I_{2}) \omega_{f}\\&or,& \omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}

Part(b):

Initial kinetic energy  

K_{i} = \dfrac{1}{2} I_{1} \omega_{i}^{2}

and Final kinetic energy

K_{f} = \dfrac{1}{2}(I_{1} + I_{2}) \omega_{f}^{2}

Substituting the value of \omega_{f},

&& K_{f} = \dfrac{1}{2}(I_{1} + I_{2})\dfrac{I_{1}^{2}\omega_{i}^{2}}{(I_{1} + I_{2})^{2}} = \dfrac{1}{(I_{1} + I_{2})} \dfrac{1}{2}I_{1}\omega_{i}^{2} = \dfrac{1}{(I_{1} + I_{2})} K_{i}\\&\dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})}

The above expression shows that the ebergy of the system will decrease.

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When a sound wave moves through a medium such as air, the motion of the molecules of the medium is in what direction (with respe
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