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lbvjy [14]
3 years ago
14

A farmer grows a particular plant that has a gene that can be manipulated to control the age t at which the plant matures. The n

umber of seeds S(t) produced by a plant maturing at age t is S(t)=−0.3t2+30t+0.2 seeds per mature plant A farmer asks the geneticists to genetically engineer a plant line that accounts for the fact that on his farm, only P(t)=90000t+100, plants mature to age t. What age of maturity should the geneticist select for the plants to maximize the seed production of the farmer's crop?a. Between 130 and 140 days b. Between 120 and 130 days
Mathematics
1 answer:
Kruka [31]3 years ago
3 0

Answer:

The correct option is;

Between 40 and 50 days

Step-by-step explanation:

The number of seeds that are produced by a plant maturing at age t, S(t), is given as follows;

S(t) = -0.3·t² + 30·t + 0.2

The proportion of plants maturing at age (t) in the plants to be engineered by the geneticist P(t) = 90000/(t + 100)

The number of seeds produced by the plants  = S(t) × P(t) = (-0.3·t² + 30·t + 0.2)×(90000/(t + 100))

To find the maximum number of seeds, we differentiate using an online tool, and equate to zero to get;

d((-0.3·t² + 30·t + 0.2)×(90000/(t + 100)))/dt = (-27000·t² - 5400000·t + 269982000)/(t + 100)² = 0

(-27000·t² - 5400000·t + 269982000)/(t + 100)² = 27000(t - 41.419)(t + 241.419)/(t + 100)² = 0

t = 41.419 or t = -241.419

Therefore, in order to maximize the production of seed of the crops of the farmer, the geneticist should select between 40 and 50 days.

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Two boats left a base camp at bearing of S60°E and S50°W at speeds of 50km/h and 70km/h respectively. Find the distance between
ivolga24 [154]

Answer:

  • 197.93 km

Step-by-step explanation:

Let the base camp is point A and boats' locations after two hours are points B and C.

By connecting the three points together we get a triangle ABC with sides:

  • AB = 50*2 = 100 km
  • AC = 70*2 = 140 km

The angle between AB and AC is:

  • 60 + 50 = 110 degrees (opposite directions from south)

We are looking for the distance BC, which can be found by using the law of cosines:

  • BC² = AB² + AC² - 2AB*AC*cos ∠BAC
  • BC² = 100² + 140² - 2*100*140*cos 110°
  • BC²  = 39176.56 (rounded)
  • BC = √39176.56 = 197.93 km (rounded)

The distance between the boats is 197.93 km.

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2 years ago
Write the place vslue of 7in 67,689
Tems11 [23]
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7,000 or seven thousand
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3 years ago
(x – 3)(4x + 2) using the distributive property. Select the answer choice showing the correct distribution
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The distributive property: a(b + c) = ab + ac

(x - 3)(4x + 2) = (x)(4x + 2) + (-3)(4x + 2)

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How to inverse this function step by step <br> f(x)=x-3/5
Nitella [24]

f(x)=x3−5

Replace f(x)

with y

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y=x3−5

Interchange the variables.

x=y3−5

Solve for y

.


Since y

is on the right side of the equation, switch the sides so it is on the left side of the equation.

y3−5=x

Add 5

to both sides of the equation.

y3=5+x

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

y=3√5+x

Solve for y

and replace with f−1(x)

.


Replace the y

with f−1(x)

to show the final answer.

f−1(x)=3√5+x

Set up the composite result function.

f(g(x))

Evaluate f(g(x))

by substituting in the value of g into f

.

(3√5+x)3−5

Simplify each term.


Remove parentheses around 3√5+x

.

f(3√5+x)=3√5+x3−5

Rewrite 3√5+x3

as 5+x

.

f(3√5+x)=5+x−5

Simplify by subtracting numbers.

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Subtract 5

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f(3√5+x)=x+0

Add x

and 0

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f(3√5+x)=x

Since f(g(x))=x

, f−1(x)=3√5+x is the inverse of f(x)=x3−5

.

f−1(x)=3√5+x

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