Question

What is the molarity of a solution made from dissolving 3.0 moles of NaCl in 250 mL of solution?

Answer 1

Answer:

$\boxed {\boxed {\sf 12 \ M \ NaCl}}$

Explanation:

Molarity, which tells us the concentration of a solution, is found by dividing the moles of solute by the liters of solution.

$M=\frac{moles \ of \ solute}{liters \ of \ solution}$

1. Define Values

There are 3.0 Moles of NaCl. This is the moles of solute.

There are 250 milliliters of solution, but we need the liters.

    a. Convert mL to L

1 milliliter is equal to 0.001 liters. We can multiply the given number of              milliliters (250) by 0.001.

250 mL * 0.001 L/mL= 0.25 L

$moles \ of \ solute = 3.0 \ mol \ NaCl \\liters \ of \ solution= 0.25 \ L$

2. Calculate Molarity

Substitute the values into the formula.

$M=\frac{3.0 \ mol \ NaCl}{0.25 \ L}$

Divide.

$M= 12 \ mol \ NaCl/L$

3. Define Units

1 mole per liter is equal to 1 molar.

Our answer of 12 mol NaCl/ L is equal to 12 M NaCl

The molarity is 12 M NaCl

Answer 2

Answer:

Molarity = 12 M

Explanation:

Given data:

Molarity of solution = ?

Number of moles of NaCl = 3.0 mol

Volume of solution = 250 mL (250/1000 = 0.25 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 3.0 mol / 0.25 L

Molarity = 12 M