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Leona [35]
2 years ago
9

The population of a town is 13,000. It decreases at a rate of 5% per year. In about how many years will the population be less t

han 12,000?
Mathematics
1 answer:
Allushta [10]2 years ago
4 0

Answer:

2 years

Step-by-step explanation:

13000 X 0.05 = 650    

13000 - 650 = 12350     year 1

12350 X 0.05 =617.5

12350 - 617.5 =11732.5     year 2

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PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST​
shusha [124]

Answer:

A. 49 + 16 (t - 1)

Step-by-step explanation:

Plug in t = 1 to test for the first hour:

49+16(1-1)=49+16(0)=49

Test as many values as you like, but testing t = 5:

49+16(5-1)=49+16(4)=49+64=113

You can see that plugging in just a few values confirms the answer.

8 0
2 years ago
3.11 unit test quadratic equations PLEASE SOLVE 25 POINTS BEING GIVEN. PLEASE DOT SCAM ME I NEED HELP
velikii [3]

Answer:

30.25 & 33.25

Step-by-step explanation:

x² + 11x + (5.5)² = 3+ (5.5)²

x² + 11x + 30.25 = 33.25

3 0
3 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
What is x-(3)/(5)=(5x)/(6)? with steps answer fast
Anettt [7]

hi

x- 3/5 =  5x/ 6  

6x - 18/5 =  5x

6x -5x =  18/5

     x = 18/5

   

let's check :      18/5 - 3/5 =  15/5 = 3

                         5 * 18/5   / 6  =    18/6 = 3

result is correct.

8 0
2 years ago
Can someone help me with my homework for free it won’t let me put my question?
Mademuasel [1]
What is it about, I’ll give it a try
8 0
2 years ago
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