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kicyunya [14]
3 years ago
11

To qualify to run in the 2005 Boston Marathon, a distance of 26.2 miles, an 18-year-old woman had to have completed another mara

thon in 3 hours and 40 minutes or less. a) To qualify, what must a woman's average speed have been in miles per hour?b) To qualify, what must a woman's average speed have been in meters per second? There are 1609 m in a mile.
Physics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

7,14545 mph and 3,1936 m/s

Explanation:

The average speed is calculated by dividing the displacement over time, then it is 26,2 miles/(3 2/3 hours), here 3 (2/3) hours is a mixed number, that represents 11/3 hours or 3,66 hours. Then the average speed is 7,14545 mph, now to turn this into meters per second, we notice as mentioned that 1 mile =1609 meters and 1 hour=3600 seconds. Then 7,14545 miles/hour* (1 hour/3600 seconds) * (1609 meters/1 mile)=3,1936 m/s

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Artemon [7]
I think its B

maybe D

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3 years ago
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Two forces, F1 = -3000 N and F2 = +1500 N acts on a plane horizontally. The craft is moving with a constant velocity of -850 m/s
jonny [76]

Because the net force must be zero, we conclude that the magnitude of the force is 1500 newtons, and the direction is in the positive axis.

<h3>What is the magnitude and direction of the third force?</h3>

By Newton's laws, we know that if the net force applied to an object is different than zero, then the object is accelerated.

In this case, we know that the object moves with constant velocity, so there is no acceleration, meaning that the net force is equal to zero.

Then we must have:

F1 + F2 + F3 = 0N

Replacing F1 and F2 we get:

-3000 N + 1500N + F3 = 0

F3 = 3000N - 1500 N = 1500N

Then the magnitude of the force is 1500 newtons, and the direction is in the positive axis.

If you want to learn more about Newton's laws, you can read:

brainly.com/question/10454047

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2 years ago
In the winter months the number of daylight hours decreases. What accounts for this change?
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Its a cause Superman superpowers are the sun so it’s every energy of powers
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3 years ago
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Verify that the linear speed of an ultracentrifuge is about 0.50 km's, and Earth in its orbit is about 30 km/s by calculating:
FrozenT [24]

Answer:

a) Indeed, the linear speed of the ultracentrifuge is 0.524 kilometers per second.

b) Indeed, the linear speed of the Earth in its orbits about the Sun is approximately 30 kilometers per second.

Explanation:

The linear speed of the particle (v), measured in kilometers per second, rotating in a circular pattern is calculated by the following formula:

v = R\cdot \omega (1)

Where:

R - Radius, measured in kilometers.

\omega - Angular speed, measured in radians per second.

Now we proceed to calculate the linear speed of each element:

a) Ultracentrifuge

If we know that \omega \approx 5235.988\,\frac{rad}{s} and R = 1\times 10^{-4}\,km, then the linear velocity is:

v = (1\times 10^{-4}\,km)\cdot \left(5235.988\,\frac{rad}{s} \right)

v = 0.524\,\frac{km}{s}

Indeed, the linear speed of the ultracentrifuge is 0.524 kilometers per second.

b) Earth

The Earth is 150 million kilometers away from the Sun and takes 365 days to complete one revolution around the Sun. First, we calculate angular speed of the planet:

\omega = \frac{2\pi}{T} (2)

Where T is the period, measured in seconds.

If we know that T = 31536000\,s, then the angular speed of the Earth is:

\omega = \frac{2\pi}{31536000\,s}

\omega = 1.992\times 10^{-7}\,\frac{rad}{s}

Now, we determine the linear speed:

v = (1.5\times 10^{8}\,km)\cdot \left(1.992\times 10^{-7}\,\frac{rad}{s} \right)

v = 29.88\,\frac{km}{s}

Indeed, the linear speed of the Earth in its orbits about the Sun is approximately 30 kilometers per second.

6 0
3 years ago
You are writing a short adventure story for your English class. In your story, two submarines on a secret mission need to arrive
levacccp [35]

Answer:

V = 31.17km/h

Explanation:

The average velocity is given by:

V = \frac{d}{t}   where d is the same distance traveled by the first submarine and t is the the same amout of time that it took.

d = 500km + 500km + 500km+ 500km = 2000km

t = t1 + t2 + t3 + t4

where

t1 = \frac{d1}{V1} = \frac{500km}{20km/h}=25h

t2 = \frac{d2}{V2} = \frac{500km}{40km/h}=12.5h

t3 = \frac{d3}{V3} = \frac{500km}{30km/h}=16.67h

t4 = \frac{d4}{V4} = \frac{500km}{50km/h}=10h

So, t = 25 + 12.5 + 16.67 + 10 = 64.17h

And finally:

V = \frac{d}{t} = \frac{2000km}{64.17h}=31.17km/h

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