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julia-pushkina [17]
3 years ago
13

Give two examples of situations or applications where electronic circuits and electric circuits are used together​

Physics
1 answer:
Natalka [10]3 years ago
3 0

The difference between both is that electric circuits makes use of relays, lighting controls, door bells e.t.c, whereas, electronic circuits deal with semiconductors that include transistors and integrated circuits.

Two examples are Smoke Detectors and Electric Toasters.

Now, the examples of two situations where both circuits are used together are;

1) Smoke Detector; In smoke detectors, there is the aspect of power which is the battery used to power the device and that operates with an electric circuit whereas the detector used to detect the smoke and make it beep is based on an electronic circuit.

2) Electric Toaster; The elements of the toaster used to heat materials operates on the principle of electric circuits while the timer used to stop the toasting is based on the principle of electronic circuits.

Read more here; brainly.com/question/24509929

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A 1.50-kg iron horseshoe initially at 550°C is dropped into a bucket containing 25.0 kg of water at 20.0°C. What is the final te
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Answer:

Te =  23.4 °C

Explanation:

Given:-

- The mass of iron horseshoe, m = 1.50 kg

- The initial temperature of horseshoe, Ti_h = 550°C

- The specific heat capacity of iron, ci = 448 J/kgC

- The mass of water, M = 25 kg

- The initial temperature of water, Ti_w = 20°C

- The specific heat capacity of water, cw = 4186 J/kgC

Find:-

What is the final temperature of the water–horseshoe system?

Solution:-

- The interaction of horseshoe and water at their respective initial temperatures will obey the Zeroth and First Law of thermodynamics. The horseshoe at higher temperature comes in thermal equilibrium with the water at lower temperature. We denote the equilibrium temperature as (Te) and apply the First Law of thermodynamics on the system:

                             m*ci*( Ti_h - Te) = M*cw*( Te - Ti_w )

- Solve for (Te):

                             m*ci*( Ti_h ) + M*cw*( Ti_w ) = Te* (m*ci + M*cw )

                             Te = [ m*ci*( Ti_h ) + M*cw*( Ti_w ) ] / [ m*ci + M*cw ]

- Plug in the values and evaluate (Te):

                             Te = [1.5*448*550 + 25*4186*20 ] / [ 1.5*448 + 25*4186 ]

                             Te = 2462600 / 105322

                             Te =  23.4 °C    

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