1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
julia-pushkina [17]
3 years ago
13

Give two examples of situations or applications where electronic circuits and electric circuits are used together​

Physics
1 answer:
Natalka [10]3 years ago
3 0

The difference between both is that electric circuits makes use of relays, lighting controls, door bells e.t.c, whereas, electronic circuits deal with semiconductors that include transistors and integrated circuits.

Two examples are Smoke Detectors and Electric Toasters.

Now, the examples of two situations where both circuits are used together are;

1) Smoke Detector; In smoke detectors, there is the aspect of power which is the battery used to power the device and that operates with an electric circuit whereas the detector used to detect the smoke and make it beep is based on an electronic circuit.

2) Electric Toaster; The elements of the toaster used to heat materials operates on the principle of electric circuits while the timer used to stop the toasting is based on the principle of electronic circuits.

Read more here; brainly.com/question/24509929

You might be interested in
A 1502.7 kg car is traveling at 33.1 m/s when
Bond [772]

By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N

If you just want the magnitude, drop the negative sign.

5 0
3 years ago
How many licks dose it take to eat a lolipop
murzikaleks [220]

Answer: Around 364 to 480

3 0
3 years ago
Read 2 more answers
A dolphin in an aquatic show jumps straight up out of the water at a velocity of 15.0 m/s. (a) List the knowns in this problem.
astra-53 [7]

Answer:

a)

Y0 = 0 m

Vy0 = 15 m/s

ay = -9.81 m/s^2

b) 7.71 m

c) 3.06 s

Explanation:

The knowns are that the initial vertical speed (at t = 0 s) is 15 m/s upwards. Also at that time the dolphin is coming out of the water, so its initial position is 0 m. And since we can safely assume this happens in Earth, the acceleration is the acceleration of gravity, which is 9.81 m/s^2 pointing downwards

Y(0) = 0 m

Vy(0) = 15 m/s

ay = -9.81 m/s^2 (negative because it points down)

Since acceleration is constant we can use the equation for uniformly accelerated movement:

Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2

To find the highest point we do the first time derivative (this is the speed:

V(t) = Vy0 + a * t

We equate this to zero

0 = Vy0 + a * t

0 = 15 - 9.81 * t

15 = 9.81 * t

t = 0.654 s

At this time it will have a height of:

Y(0.654) = 0 + 15 * 0.654 - 1/2 * 9.81 * 0.654^2 = 7.71 m

The doplhin jumps and falls back into the water, when it falls again it position will be 0 again. So we can equate the position to zero to find how long it was in the air knowing that it started the jump at t = 0s.

0 = Y0 + Vy0 * t + 1/2 * a * t^2

0 = 0 + 15 * t - 1/2 * 9.81 t^2

0 = 15 * t - 4.9 * t^2

0 = t * (15 - 4.9 * t)

t1 = 0 This is the moment it jumped into the air

0 = 15 - 4.9 * t2

15 = 4.9 * t2

t2 = 3.06 s This is the moment when it falls again.

3.06 - 0 = 3.06 s

5 0
3 years ago
If you were a pastor, and you were getting married, would you hire a pastor, or would you do the wedding yourself?
bearhunter [10]
I would hire a pastor.
4 0
3 years ago
Read 2 more answers
An electron and a proton are each placed at rest in an electric field of 500 N/C. Calculate the speed (and indicate the directio
Bumek [7]

Answer:

For proton: 2592 m/s In the same direction of electric field.

For electron: 4752000 m/s In the opposite direction of electric field.

Explanation:

E = 500 N/C, t = 54 ns = 54 x 10^-9 s,

Acceleration = Force /mass

Acceleration of proton, ap = q E / mp

ap = (1.6 x 10^-19 x 500) / (1.67 x 10^-27) = 4.8 x 10^10 m/s^2

Acceleration of electron, ae = q E / me

ae = (1.6 x 10^-19 x 500) / (9.1 x 10^-31) = 8.8 x 10^13 m/s^2

For proton:

u = 0, ap = 4.8 x 10^10 m/s^2, t = 54 x 10^-9 s

use first equation of motion

v = u + at

vp = 0 + 4.8 x 10^10 x 54 x 10^-9 = 2592 m/s In the same direction of electric field.

For electron:

u = 0, ae = 8.8 x 10^13 m/s^2, t = 54 x 10^-9 s

use first equation of motion

v = u + at

vp = 0 + 8.8 x 10^13 x 54 x 10^-9 = 4752000 m/s In the opposite direction of electric field.

6 0
3 years ago
Other questions:
  • If you let go of the notebook after pushing it, will it move?​
    5·1 answer
  • a particle with charge Q is on the y axis a distance a from the origin and a particle with charge qi is on the x axis at a dista
    5·1 answer
  • PART ONE
    9·1 answer
  • In __________ waves, the motion of the particles in a medium is across the direction of the wave (perpendicular).
    9·1 answer
  • 1 6. Which of the following astronomical units is c/osest to the distance of the earth to the sun?
    7·1 answer
  • A 2.31-kg rope is stretched between supports that are 10.4 m apart, and has a tension in it of 49.2 N. If one end of the rope is
    5·1 answer
  • Plz help help
    10·1 answer
  • Hola puntos gratis !!!!!!!!!!!!!!!!!
    6·2 answers
  • I have no idea so i'm screwed please help me
    6·1 answer
  • Once you start pulling your object with less force than friction, what should you expect your object to do? What about when your
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!