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3 years ago

One nanometer is equal to how many centimeters?

Physics

2 answers:

Rzqust [24]3 years ago

5 0

Answer:

1 cm = 10,000,000 nm

Explanation:

Since 1 meter = 100 centimeter

and 1 meter = 1,000,000,000 nanometer

so, 1 cm = 10,000,000 nm

Here we can simplify a formula to convert cm to nm as

nanometers = 10,000,000 multiplies centimeters.

Example: convert 8 cm into nms.

so nm = 10,000,000 multiplies 8

80,000,000 nms

Neko [114]3 years ago

4 0

One nanometer = 1e-7

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In a race, Usain Bolt accelerates at

jeka94

Answer:

65.87 s

Explanation:

For the first time,

Applying

v² = u²+2as.............. Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance

From the question,

Given: u = 0 m/s (from rest), a = 1.99 m/s², s = 60 m

Substitute these values into equation 1

v² = 0²+2(1.99)(60)

v² = 238.8

v = √238.8

v = 15.45 m/s

Therefore, time taken for the first 60 m is

t = (v-u)/a............ Equation 2

t = (15.45-0)/1.99

t = 7.77 s

For the final 40 meter,

t = (v-u)/a

Given: v = 0 m/s(decelerates), u = 15.45 m/s, a = -0.266 m/s²

Substitute into the equation above

t = (0-15.45)/-0.266

t = 58.1 seconds

Hence total time taken to cover the distance

T = 7.77+58.1

T = 65.87 s

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3 years ago

Why are hot springs and geysers is found in areas of present or a past activity

Lady_Fox [76]

<span>Hot springs and geysers are often found in areas of present or past volcanic activity. The hot spring forms when water deep underground is heated by a nearby body of magma or hot rock. The hot water rises and collects in a natural pool; when rising hot water and steam become trapped in a narrow crack, pressure builds until the mixture sprays above the surface as a geyser.</span>

7 0

3 years ago

What is the potential difference across a 15Ω resistor that has a current of 3.0 A?

sesenic [268]

V = I • R

V = (15 ohms) x (3 A)

V = 45 volts

6 0

3 years ago

Read 2 more answers

The fast server in women's tennis is Venus Williams, who recorded a serve of 130 mi/h (209 km/h) in 2007 If her racket pushed on

Darina [25.2K]

209 km/h = 58.0 m/s

2as = v² - u²
Assuming the ball started from rest,

a = (58)² / 2 x 0.11

a = 15,290 m/s²

7 0

3 years ago

A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.070

likoan [24]

Given Information:

length of slender rod = L = 90 cm = 0.90 m

mass of slender rod = m = 0.120 kg

mass of sphere welded to one end = m₁ = 0.0200 kg

mass of sphere welded to another end = m₂ = 0.0700 kg (typing error in the question it must be 0.0500 kg as given at the end of the question)

Required Information:

Linear speed of the 0.0500 kg sphere = v = ?

Answer:

Linear speed of the 0.0500 kg sphere = 1.55 m/s

Explanation:

The velocity of the sphere can by calculated using

ΔKE = ½Iω²

Where I is the moment of inertia of the whole setup ω is the speed and ΔKE is the change in kinetic energy

The moment of inertia of a rigid rod about center is given by

I = (1/12)mL²

The moment of inertia due to m₁ and m₂ is

I = (m₁+m₂)(L/2)²

L/2 means that the spheres are welded at both ends of slender rod whose length is L.

The overall moment of inertia becomes

I = (1/12)mL² + (m₁+m₂)(L/2)²

I = (1/12)0.120*(0.90)² + (0.0200+0.0500)(0.90/2)²

I = 0.0081 + 0.01417

I = 0.02227 kg.m²

The change in the potential energy is given by

ΔPE = m₁gh₁ + m₂gh₂

Where h₁ and h₂ are half of the length of slender rod

L/2 = 0.90/2 = 0.45 m

ΔPE = 0.0200*9.8*0.45 + 0.0500*9.8*-0.45

The negative sign is due to the fact that that m₂ is heavy and it would fall and the other sphere m₁ is lighter and it would will rise.

ΔPE = -0.1323 J

This potential energy is then converted into kinetic energy therefore,

ΔKE = ½Iω²

0.1323 = ½(0.02227)ω²

ω² = (2*0.1323)/0.02227

ω = √(2*0.1323)/0.02227

ω = 3.45 rad/s

The linear speed is

v = (L/2)ω

v = (0.90/2)*3.45

v = 1.55 m/s

Therefore, the linear speed of the 0.0500 kg sphere as its passes through its lowest point is 1.55 m/s.

8 0

3 years ago