A uniformly charged thin rod of length L and positive charge Q lies along the x-axis with its left end at the origin as shown in
Figure 1.
a. Set up a correct integral expression for the potential at point A,which lies a distance H above the right end of the rod. Point A has coordinates (L, H). You need to give appropriate limits of integration and expressions for r and dq
b. Set up a correct integral expression for the potential at point B on the x-axis, a distance D from the left end of the rod with the appropriate limits of integration.You need to give appropriate limits of integration and expressions for r and dq.
a. Set up a correct integral expression for the potential at point A,which lies a distance H above the right end of the rod. Point A has coordinates (L, H). You need to give appropriate limits of integration and expressions for r and dq
b. Set up a correct integral expression for the potential at point B on the x-axis, a distance D from the left end of the rod with the appropriate limits of integration.You need to give appropriate limits of integration and expressions for r and dq.
1 answer:
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Answer:9.75 m/s
Explanation:
Given
Length of ladder
Foot the ladder is moving away with speed of
From diagram
------1
at
Now differentiating equation 1 w.r.t time
negative indicates distance is decreasing with time
