A tennis ball (m=0.060 kg) is moving horizontally at 20 m/s toward a tennis player who hits it straight back at 26 m/s. What is
1 answer:
Answer:
0.36 kg-m/s
Explanation:
Given that,
Mass of a ball, m = 0.06 kg
Initial velocity of the ball, u = 20 m/s
Final velocity of the ball, v = 26 m/s
We need to find the change in momentum of the tennis ball. It is equal to the final momentum minus initial momentum
So, the change in momentum of the ball is 0.36 kg-m/s.
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Answer:
I = 0.287 MR²
Explanation:
given,
height of the object = 3.5 m
initial velocity = 0 m/s
final velocity = 7.3 m/s
moment of inertia = ?
Using total conservation of mechanical energy
change in potential energy will be equal to change in KE (rotational) and KE(transnational)
PE = KE(transnational) + KE (rotational)
v = r ω
I = 0.287 MR²
Answer:
E= 55.53 x 10³ V/m
Explanation:
Given that
a= 3.63 cm
Area ,A= a²
distance ,d= 0.473 mm
Stored energy ,U = 8.49 nJ
Value of capacitor given as
By putting the values
C=2.46 x 10⁻¹¹ F
V=Voltage difference
V=26.27 V
V= E d
E=Electric filed
26.27 = E x 0.473 x 10⁻³
E= 55.53 x 10³ V/m