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katen-ka-za [31]
3 years ago
13

According to the theory of global warming, the average temperature of Earth’s air began rising rapidly when humans first started

burning fuels such as oil. Burning these fuels releases carbon dioxide into the air. Scientists have observed that carbon dioxide traps heat from the Sun in Earth’s atmosphere. They have also observed ice melting in some areas.
Which part of the scientific cycle does the graph directly represent?

A.experiments
B.xplanations
C.questions
D.facts

Physics
2 answers:
ELEN [110]3 years ago
3 0

I'd say the answer to this on is d.Facts as they are using the temperatures in the graph and the temperatures are not just estimates

Illusion [34]3 years ago
3 0

Answer: D. Facts

Explanation:

A scientific cycle is a detail procedure which involves the pattern of some phenomena, making a hypothesis, making predictions based upon the hypothesis, testing the prediction on the basis of the experimental procedure, making conclusions and framing the result.

According to the given situation, D. Facts is the correct option. As the graph is directly describing the statistical output of the comparative analysis of the increase in global temperature per year due to increase in abundance of the carbon dioxide in the atmosphere.  

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The earth's radius is 6.37×106m; it rotates once every 24 hours. What is the earth's angular speed? What is the speed of a point
Zarrin [17]

Answer:

a) w = 7.27 * 10^-5 rad/s

b) v1 = 463.1 m/s

c) v1 = 440.433 m/s

Explanation:

Given:-

- The radius of the earth,  R = 6.37 * 10 ^6 m

- The time period for 1 revolution T = 24 hrs

Find:

What is the earth's angular speed?

What is the speed of a point on the equator?

What is the speed of a point on the earth's surface located at 1/5 of the length of the arc between the equator and the pole, measured from equator?

Solution:

- The angular speed w of the earth can be related with the Time period T of the earth revolution by:

                                  w = 2π / T

                                  w = 2π / 24*3600

                                  w = 7.27 * 10^-5 rad/s

- The speed of the point on the equator v1 can be determined from the linear and rotational motion kinematic relation.

                                 v1 = R*w

                                 v1 = (6.37 * 10 ^6)*(7.27 * 10^-5)

                                 v1 = 463.1 m/s

- The angle θ subtended by a point on earth's surface 1/5 th between the equator and the pole wrt equator is.

                                 π/2  ........... s

                                 x     ............ 1/5 s

                                 x = π/2*5 = 18°    

- The radius of the earth R' at point where θ = 18° from the equator is:

                                R' = R*cos(18)

                                R' = (6.37 * 10 ^6)*cos(18)

                                R' = 6058230.0088 m

- The speed of the point where θ = 18° from the equator v2 can be determined from the linear and rotational motion kinematic relation.

                              v2 = R'*w

                              v2 = (6058230.0088)*(7.27 * 10^-5)

                              v2 = 440.433 m/s

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As a mass on a spring moves farther from the equilibrium position, how do the velocity, acceleration, and force change
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