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irakobra [83]
3 years ago
13

Geosynchronous satellites orbit the Earth at a distance of 42 000 km from the Earth's center. Their angular speed at this height

is the same as the rotation rate of the Earth, so they appear stationary at certain locations in the sky. What is the force acting on a 1 500-kg satellite at this height?
Physics
1 answer:
frozen [14]3 years ago
7 0

Answer:

Force will be 7.97 N

Explanation:

We have given that earth is at s distance of 42000 km from the earth center

So r = 42000 km = 42000000 m

Mass m = 1500 kg

Angular velocity of earth \omega =7.29\times 10^{-5}rad/sec

We have to find the force

We know that force is given by

F=m\omega ^2r=1500\times (7.29\times 10^{-5})^2\times 42000000=797.1615\times 10^{-2}=7.97N

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Two common terms for a decrease in velocity are
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What are used for manufacturing paper along with wood and chemicals
Tju [1.3M]

Answer:

Paper and pulp are made from cellulosic fibers and other plant materials. Some synthetic materials may be used to impart special qualities to the finished product. Paper is made from wood fibers, but rags, flax, cotton linters, and bagasse are also used in some papers.

8 0
3 years ago
A carpenter lifts a 10-kg piece of wood to his shoulder 1.5 m above the ground. He then sets the wood on his truck at 1.0 m abov
FinnZ [79.3K]

Answer:

<em>500Joules</em>

Explanation:

Kinetic energy = 1/2mv²

m is the mass of the wood

v is the velocity

Given

Mass = 10kg

Velocity v = 10m/s

Substitute into the formula and get KE

KE = 1/2 * 10 * 10²

KE  = 1/2 * 1000

KE = 500Joules

<em>Hence the kinetic energy of the wood during delivery is 500Joules</em>

8 0
2 years ago
A 1400-kg car is traveling with a speed of 17.7 m/s. What is the magnitude of the horizontal net force that is required to bring
AleksandrR [38]

Answer:

The magnitude of the horizontal net force is 13244 N.

Explanation:

Given that,

Mass of car = 1400 kg

Speed = 17.7 m/s

Distance = 33.1 m

We need to calculate the acceleration

Using equation of motion

v^2-u^2=2as

Where, u = initial velocity

v = final velocity

s = distance

Put the value in the equation

0-(17.7)^2=2a\times 33.1

a=\dfrac{-(17.7)^2}{33.1}

a=-9.46\ m/s^2

Negative sign shows the deceleration.

We need to calculate the net force

Using newton's formula

F = ma

F =1400\times(-9.46)

F=-13244\ N

Negative sign shows the force is opposite the direction of the motion.

The magnitude of the force is

|F| =13244\ N

Hence,  The magnitude of the horizontal net force is 13244 N.

5 0
3 years ago
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