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SSSSS [86.1K]
3 years ago
9

A rubber rod with a negative 4.0 C (-4.0 x 10-6 C) charge is 10 cm east of a pith ball with a positive charge of 5.0 C. A plas

tic rod with a positive 2.0 C charge is 5.0 cm north of the pith ball.
Physics
1 answer:
AfilCa [17]3 years ago
7 0
552. cm eastthat's the answer
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At very close range, which of these forces is stronger than the gravitational force a.) electric only, b.) magnetic only c.) ele
zhenek [66]

Answer: (c) electric and magnetic

Explanation: Gravitational force is the weakest force considering short distances, relative to all other types of forces. However, it is strongest when considering large distances (such as astronomic scales).

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3 years ago
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Young's experiment is performed with light of wavelength 502nm from excited helium atoms. Fringes are measured carefully on a sc
alexandr402 [8]

Answer:

d = 1.30 mm

Explanation:

given,

wavelength of the light source (λ)= 502 nm

slits is separated (d) = ?

distance to form interference pattern(D) = 1.35 m  

20 th fringe

y = 10.4 mm = 0.0104 m

now,separation between to slits

 d = \dfrac{m\lambda\ D}{y}

where y is the fringe width

 d = \dfrac{20 \times 502\times 10^{-9}\ \times 1.35}{0.0104}

 d = \dfrac{13354\times 10^{-9}}{0.0104}

      d = 1.30 mm

separation between to slits is equal to d = 1.30 mm

8 0
3 years ago
A solid cylinder with a mass of 2.46 kg and a radius of 0.049 m starts from rest at a height of 4.80 m and rolls down a 24.3 ◦ s
irina1246 [14]

Answer:

v_{f}\approx 2.097\,\frac{m}{s}

Explanation:

Let assume that the solid cylinder rolls down a frictionless incline. The translational speed can be found by using the Principle of Energy Conservation and the Work-Energy Theorem:

m_{cyl}\cdot g\cdot y_{o} = \frac{1}{2}\cdot m_{cyl} \left( 1+ \frac{1}{R}\right)\cdot v_{f}^{2}

g\cdot y_{o} = \frac{1}{2}\cdot\left( 1+ \frac{1}{R}\right)\cdot v_{f}^{2}

The translational speed is:

v_{f} = \sqrt{\frac{2\cdot g\cdot y_{o}}{\left(1 + \frac{1}{R}  \right)}}

v_{f} = \sqrt{\frac{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (4.80\,m)}{\left(1 + \frac{1}{0.049\,m}  \right)} }

v_{f}\approx 2.097\,\frac{m}{s}

7 0
3 years ago
What holds the stars together in their galaxies? A. light B. orbits of the planets C. weight D. gravity
RUDIKE [14]
It's D. Gravity holds everything in place

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3 years ago
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two point charges are placed on x-axis a 2×10 coulomb charge at x=10cm and -1×10-6 coulomb at x=40cm calculate potential at poin
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Answer:

hshdjdjdjdb

Explanation:

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