X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
The answer will be 41/14
Step-by-step explanation:
2.928571429
Answer:
length = 48 feet , width = 32 feet
Step-by-step explanation:
Using
2W + 2L = 160 with W = L - 16 , then
2(L - 16) + 2L = 160 ← distribute and simplify left side
2L - 32 + 2L = 160
4L - 32 = 160 ( add 32 to both sides )
4L = 192 ( divide both sides by 4 )
L = 48
Substitute L = 48 into W = L - 16
W = 48 - 16 = 32
Thus length = 48 feet and width = 32 feet
Answer:
Option E 15 cm
Step-by-step explanation:
we know that
The circumference of a circle subtends a central angle of 360 degrees
so
using proportion
Find out the length of arc DE by a central angle of 45 degrees
Let
x -----> the length of arc DE
Answer:
"34,814" is the correct solution.
Step-by-step explanation:
The given values are:
Intercept coefficient,
Production coefficient,
Units sold,
x = 3,500
Now,
The total cost will be:
⇒ 
On substituting the estimated values, we get
⇒ 
⇒ 
⇒ 
