Answer:
if yoyo's string breaks it will broke
Explanation:
mark me as brainliest
Answer:
<h3>Law of reflection</h3>
Explanation:
According to the laws of reflection,
- Incident ray, reflected ray and normal lie on the same plane.
- Angle of reflection and angle of incidence are always equal.
→ Angle of reflection : Angle of which light rays reflect off surface.
→ Angle of incidence : Angle at which light rays strikes the surface.
Answer:
<u>Yes, it will be a Home Run</u>
Explanation:
(Note : It is assumed that the collision between bat and ball is perfectly elastic.)
( Also I don't know anything about baseball, so I checked the dimensions online, which are minimum 325 ft (left and right field foul pole) and minimum 400 ft centre field fence)).
<u>STEP 1</u>
<em>Find</em><em> </em><em>Horizontal</em><em> </em><em>Range</em><em> </em><em>of</em><em> </em><em>Projectile</em><em> </em>
Therefore, the ball will travel 560.3 ft horizontally well beyond 400 ft (largest dimension of the field), and it'll be a Home Run.
Answer:
v₀ = 49.5 miles / h
Explanation:
We can solve this exercise with kinematics in one dimension
v² = v₀² - 2 a d
let's apply this equation to the initial data, the fine velocity zero
0 = v₀² - 2 a d
a = v₀² / 2d
in the second case the distance is half (d´ = ½ d), the acceleration of the vehicle is the same, we look for the initial speed
0 = v₀´² - 2 a d´
v₀´² = 2 a d = 2 (v₀² / 2d) d´
v₀´ = v₀ √ 1/2
let's calculate
v₀´ = 70 ra 0.5
v₀ = 49.5 miles / h
Answer:
The initial speed of the ball is 3.93 m/s.
Explanation:
It is given that,
A ball is thrown horizontally from a height of 19 m, h = 19 m
Let u is the initial speed of the ball so, its final velocity, v = 5u
Using third equation of motion as :
u = 3.93 m/s
So, the initial speed of the ball is 3.93 m/s. Hence, this is the required solution.