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wolverine [178]
3 years ago
12

I don't want the answer i just need help on figuring out how to solve this!

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

<u>Yes, it will be a Home Run</u>

Explanation:

(Note : It is assumed that the collision between bat and ball is perfectly elastic.)

( Also I don't know anything about baseball, so I checked the dimensions online, which are minimum 325 ft (left and right field foul pole) and minimum 400 ft centre field fence)).

<u>STEP 1</u>

<em>Find</em><em> </em><em>Horizontal</em><em> </em><em>Range</em><em> </em><em>of</em><em> </em><em>Projectile</em><em> </em>

R =  \frac{ {u}^{2} \sin(2 \alpha )  }{g}  =  \frac{(49.1)^{2}  \sin(44°) }{g}

R = 170.8 \: m \:  = 560.3 \: ft

Therefore, the ball will travel 560.3 ft horizontally well beyond 400 ft (largest dimension of the field), and it'll be a Home Run.

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A well lagged copper calorimeter of mas 120g contains 70g of water and 10g ice both at 0°C . Dry steam at 100°C is passed in unt
Lina20 [59]

Answer:

7.6 g

Explanation:

"Well lagged" means insulated, so there's no heat transfer between the calorimeter and the surroundings.

The heat gained by the copper, water, and ice = the heat lost by the steam

Heat gained by the copper:

q = mCΔT

q = (120 g) (0.40 J/g/K) (40°C − 0°C)

q = 1920 J

Heat gained by the water:

q = mCΔT

q = (70 g) (4.2 J/g/K) (40°C − 0°C)

q = 11760 J

Heat gained by the ice:

q = mL + mCΔT

q = (10 g) (320 J/g) + (10 g) (4.2 J/g/K) (40°C − 0°C)

q = 4880 J

Heat lost by the steam:

q = mL + mCΔT

q = m (2200 J/g) + m (4.2 J/g/K) (100°C − 40°C)

q = 2452 J/g m

Plugging the values into the equation:

1920 J + 11760 J + 4880 J = 2452 J/g m

18560 J = 2452 J/g m

m = 7.6 g

7 0
3 years ago
A 4-kg object is moving with a speed of 5 m/s at a height of 2 m. The kinetic
tatyana61 [14]

Hello!

\large\boxed{KE = 50J}

Use the formula for kinetic energy:

KE = \frac{1}{2}mv^{2}

Plug in the given mass and velocity:

KE = \frac{1}{2} (4)5^{2}

Simplify:

KE = \frac{1}{2} (100)\\\\KE = 50 J

7 0
3 years ago
PLEASE HELP ME ON THIS ONE ANYONE
andreev551 [17]

Answer:

A & B

Explanation:

A & B Would be the right answer since Morse code cannot be represented through the height of the fire.

6 0
2 years ago
What is true for ALL of the examples of electromagnetic waves? A) They all move at the same speed in a vacuum. B) They all have
gizmo_the_mogwai [7]

<em>A statement that is true for ALL of the examples of electromagnetic waves is that;</em>

A) They all move at the same speed in a vacuum

<u>The reason for qualifying 'in vacuum' is because EM waves of different frequencies often propagate at different speeds through material. Generally speaking, we say that light travels in waves, and all electromagnetic radiation travels at the same speed which is about 3.0 * 108 meters per second through a vacuum.</u>

5 0
3 years ago
Read 2 more answers
A flow is isentropically expanded to supersonic speeds in a convergent-divergent nozzle. The reservoir and exit pressures are 1.
Kamila [148]

Answer:

Ae/A* = 1.115

Explanation:

Let the reservoir pressure be  p_0

Let the exit  pressure be p_e

Ratio of reservoir pressure and exit pressure

\frac{p_o}{p_e} = \frac{1}{0.3143}

  = 3.182

For the above value of pressure ratio

Obtain the area ratio from the isentropic flow table

Ae/A* = 1.115

The value of pressure ratio is Ae/A* = 1.115

6 0
3 years ago
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