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wolverine [178]
3 years ago
12

I don't want the answer i just need help on figuring out how to solve this!

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

<u>Yes, it will be a Home Run</u>

Explanation:

(Note : It is assumed that the collision between bat and ball is perfectly elastic.)

( Also I don't know anything about baseball, so I checked the dimensions online, which are minimum 325 ft (left and right field foul pole) and minimum 400 ft centre field fence)).

<u>STEP 1</u>

<em>Find</em><em> </em><em>Horizontal</em><em> </em><em>Range</em><em> </em><em>of</em><em> </em><em>Projectile</em><em> </em>

R =  \frac{ {u}^{2} \sin(2 \alpha )  }{g}  =  \frac{(49.1)^{2}  \sin(44°) }{g}

R = 170.8 \: m \:  = 560.3 \: ft

Therefore, the ball will travel 560.3 ft horizontally well beyond 400 ft (largest dimension of the field), and it'll be a Home Run.

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How much must a woman weigh ( force) if the pressure she exerts while standing on one foot has an area of 0.6m squared exerts a
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P=\dfrac{F}{A}\\\\P=\dfrac{W}{A}\\\\W=16\times 0.6\\\\W=9.6\ N

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What is the acceleration of the box?
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Answer:

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Consider two massless springs connected in series. Spring 1 has a spring constant k1, and spring 2 has a spring constant k2. A c
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Answer:

a. k = (1/k₁ + 1/k₂)⁻¹ b. k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

Explanation:

Since only one force F acts, the force on spring with spring constant k₁ is F = k₁x₁ where x₁ is its extension

the force on spring with spring constant k₂ is F = k₂x₂ where x₁ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂

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k = (1/k₁ + 1/k₂)⁻¹

B

The force on spring with spring constant k₃ is F = k₃x₃ where x₃ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂ + x₃

x = F/k = F/k₁ + F/k₂ + F/k₃

1/k = 1/k₁ + 1/k₂ + 1/k₃

k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

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