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marta [7]
2 years ago
11

How big is the universe? sorry this is so random

Physics
1 answer:
prisoha [69]2 years ago
6 0

Answer:

Explanation: 46 billion light years I think

Aww I wanted brainliest:( be doggo, doggo sad :(

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Lab number 14: sudden stops hurt newtons first law
kompoz [17]

Answer:

you want to know newtons first law here.

Explanation:

An object that is at rest stays at rest or stays in motion.

7 0
3 years ago
Which of the following statements about floating objects is always true? a. The object’s density is greater than the density of
Yuki888 [10]
It should be C. If the object is denser than the fluid, it will sink. If it isn't, it will float
6 0
3 years ago
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An object of mass m = 5.0 kg hangs from a cord around a light pulley: The length of the cord between the oscillator and the pull
puteri [66]

Answer:

\mu=0.0049Kg/m

Explanation:

When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:

f_n=\frac{nv}{2L}

Where L is the length of the string and v the velocity of propagation. Use this expression to find the value of v.

f_6=\frac{6v}{2L}\\(150)=\frac{6v}{2(2)} \\150=\frac{3v}{2} \\3v=150(2)\\ v=\frac{300}{3} \\v=100m/s

The velocity of propagation is given by the expression:

v=\sqrt{\frac{T}{\mu }

Where \mu is the desirable variable of the problem, the linear mass density, and T is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:

T=W=mg=(5)(9.81)=49.05N

With the value of the tension and the velocity you can find the mass density:

v=\sqrt{\frac{T}{\mu}

v^2=\frac{T}{\mu}\\ \mu=\frac{T}{v^2} =\frac{49.05}{(100)^2} =\frac{49.05}{10000} =0.0049Kg/m

6 0
3 years ago
Describe how the properties of sound waves change as they spread out in a spherical pattern.
guapka [62]
They go up and down
4 0
2 years ago
3.25 kcal is the same amount of energy as
PIT_PIT [208]
<span>1 cal = 4,185 J
1 kcal = 1*10^3 cal
or
=1000 cal</span>
8 0
3 years ago
Read 2 more answers
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