Hi friends any lover mates be mine wannt
2 answers:
You might be interested in
Answer:
Acceleration of the bags is 0.861 m/s²
Explanation:
Given:
Mass of the rock, m = 22.5 kg = mass of the food
Slope, Θ = 55.5°
Now, from the figure, we have
T - mgsinΘ = ma ...................(1)
'a' is the acceleration of the mass
where T is the tension
also for the second mass, we have
mg - T = ma
now substituting the value of T from the equation (1) we get
mg - (ma + mgsinΘ) = ma
or
mg(1 - sinΘ) = (m + m)a
or
a =
on substituting the values we get
a =
or
a = 0.861 m/s²
Hence, the acceleration of the bags is 0.861 m/s²
Answer:
Weight=686.7N, , S.G.=0.933, F=17.5N
Explanation:
So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:
W=mg
so we can substitute the data the problem provided us with to get:
which yields:
W=686.7N
Next, we need to find the density of methanol, which can be found by using the following formula:
we know the volume of methanol is 75L, so we can convert that to like this:
so we can now use the density formula to find our the methanol's density, so we get:
Next, we can us these values to find the specific gravity of methanol by using the formula:
when substituting the known values we get:
so:
S.G.=0.933
We can now find the force it takes to accelerate this tank linearly at
F=ma
F=17.5N