An astronaut on Earth notes that in her soft drink an ice cube floats with 9/10 of its volume submerged. If she were instead in
2 answers:
Answer:
B) with 9/10 submerged
Explanation:
= mass of ice cube
= density of soft drink
= Volume of soft drink displaced
ice cube floats in the soft drink when the force of buoyancy on it balances its weight. Force of buoyancy acting on the cube in upward direction is same as the weight of the soft drink displaced. hence we can write
weight of ice cube = weight of soft drink displaced
we see that the acceleration due to gravity cancel out both side and hence it does affect as astronaut is on earth on in a lunar module.
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Answer:
a) The total angle of the grinding wheel is 569.88 radians, b) The grinding wheel stop at t = 12.354 seconds, c) The deceleration experimented by the grinding wheel was 8.780 radians per square second.
Explanation:
Since the grinding wheel accelerates and decelerates at constant rate, motion can be represented by the following kinematic equations:
Where:
,
- Initial and final angular position, measured in radians.
,
- Initial and final angular speed, measured in radians per second.
- Angular acceleration, measured in radians per square second.
- Time, measured in seconds.
Likewise, the grinding wheel experiments two different regimes:
1) The grinding wheel accelerates during 2.40 seconds.
2) The grinding wheel decelerates until rest is reached.
a) The change in angular position during the Acceleration Stage can be obtained of the following expression:
If ,
and
, then:
The final angular angular speed can be found by the equation:
If ,
and
, then:
The total angle that grinding wheel did from t = 0 s and the time it stopped is:
The total angle of the grinding wheel is 569.88 radians.
b) Before finding the instant when the grinding wheel stops, it is needed to find the value of angular deceleration, which can be determined from the following kinematic expression:
The angular acceleration is now cleared:
Given that ,
and
, the angular deceleration is:
Now, the time interval of the Deceleration Phase is obtained from this formula:
If ,
and
, the time interval is:
The total time needed for the grinding wheel before stopping is:
The grinding wheel stop at t = 12.354 seconds.
c) The deceleration experimented by the grinding wheel was 8.780 radians per square second.