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Dmitrij [34]
4 years ago
5

Batman, whose mass is 122 kg, is holding on to the free end of a 6.89 m rope, the other end of which is fixed to a tree limb abo

ve. He is able to get the rope in motion as only Batman knows how, eventually getting it to swing enough that he can reach a ledge when the rope makes a 77.8 ◦ angle with the vertical. The acceleration of gravity is 9.8 m/s 2 . How much work was done against the force of gravity in this maneuver? Answer in units of J.
Physics
1 answer:
Debora [2.8K]4 years ago
6 0

Answer:

6496.854532 J

Explanation:

m = Mass of batman = 122 kg

g = Acceleration due to gravity = 9.8 m/s²

The distance to the ground is given by

h=6.89-6.89cos77.8\\\Rightarrow h=5.43397\ m

The work done will be the potential energy

W=mgh\\\Rightarrow W=122\times 9.8\times 5.43397\\\Rightarrow W=6496.854532\ J

The work done against the force of gravity in this maneuver is 6496.854532 J

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A force acts on a 9.90 kg mobile object that moves from an initial position of to a final position of in 5.40 s. Find (a) the wo
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Given that,

Mass of object = 9.90 kg

Time =5.40 s

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s= -6.80i+6.20j-0.1k

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Using formula of power

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P=\dfrac{41.67}{5.40}

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(c). We need to calculate the angle between vectors

Using formula of angle

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Put the value into the formula

\theta=\cos^{-1}\dfrac{(-4.10i + 3.30j + 5.40k)\cdot(2.70i - 2.90j + 5.50k)}{7.54\times6.778})

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Hence, (a). The work done on the object by the force in the 5.40 s interval is 41.67 J.

(b). The average power due to the force during that interval is 7.71 Watt.

(c).  The angle between vectors is 79.7°

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