Hey mate
Here is your answer
Option A)
Explanation:
The larger the amplitude of the waves, the louder the sound. Pitch (frequency) – shown by the spacing of the waves displayed. The closer together the waves are, the higher the pitch of the sound.
Pls mark as brainliest
Answer:
3k mph
Explanation:
don't take my answer it is wrong
Answer:
B. They each contain the same amount of matter.
Explanation:
Scientifically, mass is the amount of matter in an object.
A. Whether an object is big or small does not mean that it will be a certain mass. If you have two objects that are the same size, the denser object will have more mass, and the less dense object will have less mass.
C. The amount of space an object takes up is called the volume.
D. Different combinations and amounts of elements can give you the same mass. Rocks, books and cans of soda are made of different things.
Think of a wedge as something you put in between objects, so it is a separates objects
Answer:
The final velocity of the car A is -1.053 m/s.
Explanation:
For an elastic collision both the kinetic energy and the momentum of the system are conserved.
Let us call
= mass of car A;
= the initial velocity of car A;
= the final velocity of car A;
and
= mass of car B;
= the initial velocity of car B;
= the final velocity of car B.
Then, the law of conservation of momentum demands that
![m_Av_{A1}+m_Bv_{B1} =m_Av_{A2}+m_Bv_{B2}](https://tex.z-dn.net/?f=m_Av_%7BA1%7D%2Bm_Bv_%7BB1%7D%20%3Dm_Av_%7BA2%7D%2Bm_Bv_%7BB2%7D)
And the conservation of kinetic energy says that
![\dfrac{1}{2} m_Av_{A1}^2+\dfrac{1}{2}m_Bv_{B1}^2=\dfrac{1}{2}m_Av_{A2}^2+\dfrac{1}{2}m_Bv_{B2}^2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%20m_Av_%7BA1%7D%5E2%2B%5Cdfrac%7B1%7D%7B2%7Dm_Bv_%7BB1%7D%5E2%3D%5Cdfrac%7B1%7D%7B2%7Dm_Av_%7BA2%7D%5E2%2B%5Cdfrac%7B1%7D%7B2%7Dm_Bv_%7BB2%7D%5E2)
These two equations are solved for final velocities
and
to give
![$v_{A2} =\frac{m_A-m_B}{m_A+m_B} v_{A1}+\frac{2m_B}{m_A+m_B} v_{B1}$](https://tex.z-dn.net/?f=%24v_%7BA2%7D%20%3D%5Cfrac%7Bm_A-m_B%7D%7Bm_A%2Bm_B%7D%20v_%7BA1%7D%2B%5Cfrac%7B2m_B%7D%7Bm_A%2Bm_B%7D%20v_%7BB1%7D%24)
![$v_{B2} =\frac{2m_A}{m_A+m_B} v_{A1}+\frac{m_B-m_A}{m_A+m_B} v_{B1}$](https://tex.z-dn.net/?f=%24v_%7BB2%7D%20%3D%5Cfrac%7B2m_A%7D%7Bm_A%2Bm_B%7D%20v_%7BA1%7D%2B%5Cfrac%7Bm_B-m_A%7D%7Bm_A%2Bm_B%7D%20v_%7BB1%7D%24)
by putting in the numerical values of the variables we get
![$v_{A2} =\frac{281-209}{281+209} (2.82)+\frac{2*209}{281+209} (-1.72)$](https://tex.z-dn.net/?f=%24v_%7BA2%7D%20%3D%5Cfrac%7B281-209%7D%7B281%2B209%7D%20%282.82%29%2B%5Cfrac%7B2%2A209%7D%7B281%2B209%7D%20%28-1.72%29%24)
![\boxed{v_{A2} = -1.05m/s}](https://tex.z-dn.net/?f=%5Cboxed%7Bv_%7BA2%7D%20%3D%20-1.05m%2Fs%7D)
and
![$v_{B2} =\frac{2*281}{281+209} (2.82)+\frac{209-281}{281+209} (-1.72)$](https://tex.z-dn.net/?f=%24v_%7BB2%7D%20%3D%5Cfrac%7B2%2A281%7D%7B281%2B209%7D%20%282.82%29%2B%5Cfrac%7B209-281%7D%7B281%2B209%7D%20%28-1.72%29%24)
![\boxed{v_{B2} = 3.49m/s}](https://tex.z-dn.net/?f=%5Cboxed%7Bv_%7BB2%7D%20%3D%203.49m%2Fs%7D)
Thus, the final velocity of the car A is -1.053 m/s and of car B is 3.49 m/s.