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exis [7]
3 years ago
15

How many liters of oxygen are needed to react completely with 81.0 g of aluminum at STP?

Chemistry
2 answers:
matrenka [14]3 years ago
4 0
I think is C
Al= 108g have Vo2= 67.2L
Al= 81.0g have Vo2= ?
What you need to do is:
67.2 multiply with 81.0 and divided by 108 you will see the answer which is 50.4 L
Gelneren [198K]3 years ago
3 0

Answer:

Volume O₂ at STP = 50.4 Liters

Explanation:

4Al(s) + 3O₂(g) => 2Al₂O₃(s) at STP conditions

81g Al(s) = 81g/27g/mole = 3mole Al

moles O₂ consumed = 4/3(3)moles O₂ = 2.25 moles O₂ consumed

Volume O₂ at STP = 2.25moles x 22.4L/mole = 50.4 Liters O₂

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Iron has a density of 7.87 g/cm3. What is the volume in cm3 of 3.729 g of iron?
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If iron has a density of 7.87g/cm³ and a mass of 3.729g, then the volume of iron is 0.474cm³

HOW TO CALCULATE VOLUME:

  • The volume of a substance can be calculated by dividing the mass by its density. That is;

Volume (mL) = mass (g) ÷ density (g/mL)

  • The density of iron is given as 7.87g/cm³ while its mass is 3.729g of iron. Hence, the volume can be calculated as follows:

Volume = 3.729 ÷ 7.87

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Therefore, the volume of iron is 0.474cm³

Learn more: brainly.com/question/2040396?referrer=searchResults

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