When a solution of Pb(NO3)2(aq) is mixed with a solution of KI(aq), a precipitate of PbI₂ will form; K⁺ and NO₃⁻ are spectator ions.
<u>Explanation:</u>
When an aqueous solution of lead nitrate (Pb(NO₃)₂ is mixed with aqueous solution of potassium iodide (KI), then there is a precipitate formation of lead iodide (PbI₂), and the potassium (K⁺) ion and nitrate (NO₃⁻) ion acts as spectator ions that is ions do not involved in the reaction.
The reaction can be represented as,
Pb(NO₃)₂(aq) + 2 KI (aq) → PbI₂(s) + 2KNO₃(aq)
The ionic equation can be written as,
Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + 2 I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
On both sides of the equation, we have K⁺ and NO₃⁻ ions, which gets cancelled, and these 2 ions are called as spectator ions.
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The solution with the lowest pH would mean that it is an acid, specifically a strong acid which completely dissociates into ions in aqueous solution. Among the choices listed above, I think the correct answer is option D. It is nitric acid that will have the lowest pH because it is the only strong acid in the group.
For the equilibrium that exists in an aqueous solution<span> of nitrous acid (</span>HNO2, a weak acid) ... [H+][NO2. –]. [HNO2<span>]. PAGE: 14.1. 2. Which of the following is a conjugate ... Using the following Ka values, indicate the correct </span>order<span> of base strength. </span>HNO2<span>. Ka = </span>4.0<span> × 10–4 .... Calculate the [H+] in a </span>solution<span>that has a </span>pH<span> of 11.70.
i hope thid works
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Hi there!
I answered a question for you earlier and confused it with this question.
The answer is: B. Transverse
Happy learning!
~Brooke