Answer:
f(x) = 2x^2 - 6x - 20.
Step-by-step explanation:
(-2, 0) and (5, 0) are 2 zeroes of the function so we can write the function as
f(x) = a(x + 2)(x - 5) where a is a constant.
Now as (4, -12) is a point on the graph:
-12 = a(4 + 2)(4 - 5)
-12 = a * 6 * -1
-6a = -12
a = 2.
So f(x) = 2(x + 2)(x - 5)
f(x) = 2x^2 - 6x - 20.
Answer:
y= 13/2x +12
Step-by-step explanation:
so first move expression to right hand side
13x-2y+24=0
2y= 13x+24
then divide every term by 2 to cancel out 2
2y/2 = 13x/2 + 24/2
and then you get your final answer
The answer is C. If you substitute x for 6 and , the equation looks like this:
2(1+6)>5+8
Solve.
2(7)>13
14>13
Since 14 is greater than 13, the values make the statement true
First, let's put that line in standard form
y - 3 = 3(x + 1)
y - 3 = 3x + 3
y = 3x + 6
(Standard form is y = mx+b, where m is slope and b is y-intercept.)
Now, a line parallel to that line would have the same slope of 3. So now we have m = 3. Plug that in for m and now we have
y = 3x + b
But we still need the b value. We can get that by plugging in the point (0, -3)
(-3) = 3(0) + b
-3 = 0 + b
b = -3
Now put b back into the equation and your final equation is
y = 3x - 3
