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2 years ago

Find the value of the triangle shown below X=

Mathematics

1 answer:

SpyIntel [72]2 years ago

7 0

This is a isosceles triangle. all sides degrees added together (triangle) is equal to 180.

we know one side is 55°, and since its isosceles, it will be congruent on both sides. so there are 2 55°.

since the sum of all angles is 180°, the equation will be 55°+55°+x=180

combine like terms (55+55), which equals to 110.

last, 180-110 = 70

so the answer will be x = 70°

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2 years ago

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baherus [9]

Answer:

divide 500 by 125.

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2 years ago

A wheel turns through 90 revolutions per minute how many degrees does it turn through in 1 second

suter [353]

Answer:

540°

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3 years ago

Read 2 more answers

Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su

weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

$\Delta =305-189=116$ Maximum value - Minimum value for weight

Mean:

$\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds$

Variance:

$s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\$

The Standard Deviation of the sample

$s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\$

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

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3 years ago

The management of a restaurant with locations all over the country has developed a new hamburger that researchers believe will s

Sliva [168]

Using sampling concepts, it is found that the best way to perform a randomized experiment with the goal of determining if this new hamburger will sell better than the hamburger that is currently sold is as follows:

Randomly select 40 restaurants, let each one decide if it wants to sell the new hamburger, and compare sales in those restaurants to sales in the restaurants that chose not to sell the new hamburger.

<h3>What is sampling?</h3>

It is is a common statistics practice, when we want to study something from a population, we find a sample of this population.

For example:

I want to estimate the proportion of New York state residents who are Buffalo Bills fans. So i ask, lets say, 1000 randomly selected New York state residents whether they are Buffalo Bills fans, and expand this to the entire population of New York State residents.

In this problem, a sample of randomly selected restaurants should be taken to sell the new hamburger, and then be compared with the ones who sell the old hamburger to see if sales increased, hence the correct option is:

Randomly select 40 restaurants, let each one decide if it wants to sell the new hamburger, and compare sales in those restaurants to sales in the restaurants that chose not to sell the new hamburger.

More can be learned about sampling concepts at brainly.com/question/25122507

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2 years ago