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pishuonlain [190]
3 years ago
7

What is the gravitational potential energy of a 5 kg object that is 150

Chemistry
2 answers:
marusya05 [52]3 years ago
5 0

Explanation:

Gravitational potential energy

= mgh

= (5kg)(9.81N/kg)(150m)

= 7357.5J.

omeli [17]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 7350 \ Joules}}

Explanation:

Gravitational potential energy can be found using the following formula:

E_P=m*g*h

Where <em>m</em> is the mass, <em>g</em> is the gravitational acceleration, and <em>h</em> is the height.

The mass of the object is 5 kilograms. On Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 150 meters.

m= 5 \ kg \\g= 9.8 \ m/s^2 \\h= 150 \ m

Substitute the values into the formula.

E_p=(5 \ kg)(9.8 \ m/s^2)(150 \ m)

Multiply the first two numbers.

E_P=(49 \ kg*m/s^2)(150 \ m)

  • 1 kg*m/s² is equal to 1 Newton.
  • 49 kg*m/s²= 49 N

E_p=(49 \ N)(150 \ m)

Multiply.

E_p=7350 \ N*m

  • 1 Newton meter equals 1 Joule
  • 7350 N*m= 7350 J

E_p= 7350 \ J

The gravitational potential energy of the object is <u>7350 Joules</u>

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Answer:

Soap decreases surface tension by changing the way water behaves on the surface. Hard and soft water react differently when soap is added to them.

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8 0
3 years ago
A. Consider the following neutral electron configurations in which n has a constant value. Which configuration would belong to t
NeTakaya

Answer:

2s2 2p5

Rb < Sr< Sn< Te<I

Explanation:

Electron affinity is the ability of an atom to accept electrons to form negative ions.

Electron affinity is a periodic trend that decreases down the group but increases across the period.

This accounts for the trends observed in the answer. The atom having the electronic configuration, 2s2 2p5 must be a halogen and it exhibits the highest value of electron affinity.

Also, since electron affinity increases across the period, the electron affinities of the elements increases. Therefore, the arrangement of atoms as shown in the answer depends on increasing electron affinity.

6 0
3 years ago
A reaction mixture initially contains 0.140 MCO and 0.140 MH2O. What will be the equilibrium concentration of CO?
Allushta [10]

Answer:

0.013 M

Explanation:

From the question, we can make the following deductions; we are given mixture that contains two compounds, that is A and B, 0.140 M CO and 0.140 M H2O respectively. Then, we are asked to find the equilibrium concentration of Carbonmonoxide,CO.

So, the equation for the reaction is given below;

CO + H2O <-----------------> CO2 + H2.

Initially: we have 0.14M of CO, 0.14M of H2O and zero (0) concentration of CO2 and H2.

At time,t = CO =0.14 - x , H2O = 0.14 - x, CO2 and H2 = x.

The above reaction consist of the forward reaction and the backward reaction.

Therefore, the equilibrium Concentration of CO;

(Since we are giving that Kc = 102). Then, Kc=  [CO2][H2] ÷ [CO][H2O]. Where Kc is the equilibrium constant.

Therefore, 102 = [x^2] / [0.14 - x]^2.

==> 10.1= x/0.14 - x.

====> 0.141 - 10.1 x = x.

x + 10.1 x = 0.141.

===> 11.1 x = 0.141.

===> x = 0.141 ÷ 11.1.

===> x = 0.127 M .

Then, at time,t CO = 0.14 - x.

= 0.14 - 0.127 = 0.013 M

8 0
4 years ago
Read 2 more answers
What became of alchemy after the 1700s
Dvinal [7]
Chemistry developed from alchemy after the 1700s. It was the Alchemist <span>observations and accidental discoveries that brought around modern chemistry.</span>
6 0
3 years ago
In an acid-base titration, a student uses 21.35 mL of 0.150 M NaOH to neutralize 25.00 mL of H2SO4. How many moles of acid are i
GalinKa [24]

Answer: There are 0.006 moles of acid in the flask.

Explanation:

Given: V_{1} = 21.35 mL,        M_{1} = 0.150 M

V_{2} = 25.0 mL,           M_{2} = ?

Formula used to calculate molarity of H_{2}SO_{4} is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M

As molarity is the number of moles of a substance present in a liter of solution.

Total volume of solution = V_{1} + V_{2}

= 21.35 mL + 25.0 mL

= 46.36 mL  (1 mL = 0.001 L)

= 0.04636 L

Therefore, moles of acid required are calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol

Thus, we can conclude that there are 0.006 moles of acid in the flask.

3 0
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