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3 years ago

Please Help ASAP! Will Mark Brainliest

Chemistry

2 answers:

CaHeK987 [17]3 years ago

8 0

Answer:

35. boiling point 100 Celsius

36. seven

sorry i dont know 37 AND 38. :(

Explanation:

blsea [12.9K]3 years ago

5 0

Answer: 35. it is 100°C

36. there is 7 periods in the periodic table

37. A heterogeneous mixture consists of visibly different substances or phases. ... Solutions have particles which are the size of atoms or molecules - too small to be seen. Oil and water form a heterogeneous or cereal and milk also makes a heterogeneous. a example of solution mixture is salt and water or rubbing alcohol.

38. A two phase mixture is a mixture of two different substances. An example of a two phase mixture would be a soft drink. It is a liquid and a gas. To separate these two substances you could heat the liquid and then capture the carbon dioxide.

Explanation:

I hope this helps you out buddy stay safe

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8.41 x 10 to the -7 grams to microgram

mezya [45]

0.841 micrograms is the answer.

If you have any questions, let me know.

6 0

3 years ago

Which of the following is a reasonable ground-state electron configuration?A) 1s21p62d2B) 1s22s42p6C) 1s22s22p5D) 1s22s22d6

Semenov [28]

Answer:

Option C) 1s² 2s² 2p⁵

Explanation:

Ground-state is the configuration of the electrons when every electron of the atom occupies the lowest possible energy level.

The rank of energy of the orbitals may be remembered using Aufbau rules, and it is:

1s² < 2s² < 2p⁶ < 3s² < 3p⁶ < 4s² < 3d¹⁰ < 4p⁶ < 5s² < 4d¹⁰ < 5p⁶ < 6s² < 4f¹⁴ < 5d¹⁰ < 6p⁶ < 7s² < 5f¹⁴ < 6d¹⁰ < 7p⁶

Then, to find whether an electron configuration corresponds to a ground-state one, you must check that the previous order is preserved.

Option A). 1s² 1p⁶ 2d²

The orbital 1p does not exist. So this one is discarded.

Option B) 1s² 2s⁴ 2p⁶

The maximum number of electrons in an s orbital is 2, so 2s⁴ is impossible, and this option is discarded.

Option C) 1s² 2s² 2p⁵

This is correct because the orbitals are filled in the correct increasing energy order, without jumping any one.

Option D) 1s² 2s² 2d⁶

Orbital 2d does not exist, so this option is also discarded.

4 0

3 years ago

How do I answer and do this

Alecsey [184]

a) When the reaction takes place a yellow precipitate will be formed.

b) The law of conservation of mass is true.

Explanation:

a) When a lead nitrate solution is mixed with a potassium chromate solution, a yellow precipitate containing lead forms according to the equation:

$Pb(NO_3)_2 (aq) + K_2CrO_4 (aq)$ → $2 KNO_3 (aq) + PbCrO_4(s).$

b) Law of conservation of mass for the given reaction is true.

From the given table we know the mass of reactants and its products.

Law of conservation of mass is a principle when a reaction takes place in a closed system, the mass of the products and reactants in the system doesn't change.

⇒The sum of the mass of the reactants = The sum of the mass of the products.

The sum of the reactants = 128.71+128.97.

= 257.68 g.

The sum of the products = 154.10+103.58.

= 257.68 g.

Thus law of conservation of mass is true for the above reaction.

3 0

3 years ago

Consider the following reaction: C6H6 + O2 \longrightarrow ⟶ CO2 + H2O 39.7 grams of C6H6 are allowed to react with 105.7 g of O

Ivenika [448]

Answer:

116.3 grCO2

Explanation:

1st - we balance the equation so that it finds the same amount of elements of the product side and of the reagent side

C6H6 +15/2 O2⟶ 6CO2 +3 H2O

2nd - we calculate the limiting reagent

39.2gr C6H6*(240grO2/78grC6H6)=120 grO2

we don't have that amount of oxygen so this is the excess reagent and oxygen the limiting reagent

3rd - we use the limiting reagent to calculate the amount of CO2 in grams

105.7grO2*(264grCO2/240grO2)=116.3 grCO2

7 0

3 years ago

Can someone help me with #35,37,39,41 please

adoni [48]

35 b.
37 h
39 i
41 d
hope that helps

4 0

3 years ago