Answer:
q > 4
Step-by-step explanation:
Step 1: Write inequality
7 < 4q - 9
Step 2: Solve for <em>q</em>
<u>Add 9 to both sides:</u> 16 < 4q
<u>Divide both sides by 4:</u> 4 < q
Here, we can see that any number greater than 4 will work. So even 23573489079357 would work, as long as it is greater than 4.
Answer:
36/60
Step-by-step explanation:
There are 60 minutes in an hour
4.
4x3=12
12+5=17
Therefore, the answer is 4.
Answer:
7.5 days
Step-by-step explanation:
Answer:
i) 
\frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}
ii)
4^{3} + 8^{2} + \sqrt{9}
iii) ![(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}](https://tex.z-dn.net/?f=%28%5Cfrac%7B4%7D%7B5%7D%29%5E%7B2%7D.%20%5Csqrt%5B3%5D%7B8%7D%20%5Cleqx%5E%7B3%7D%20-%203x%20%2B%206%20%5Cleq%20%5Csqrt%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5CRightarrow%20%5Chspace%7B0.2cm%7D)
(\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}
Step-by-step explanation:
i) \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}
ii) 4^{3} + 8^{2} + \sqrt{9}
iii) (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}
