A mover is pushing a box up a ramp into his moving truck. What forces are being applied on the box? (Consider which forces are b
1 answer:
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A) 13.2 m
The motion of the skier is a projectile motion, which consists of two independent motions:
- a horizontal motion with constant speed
- a vertical motion with constant acceleration (acceleration of gravity) downward
To find the maximum height of her trajectory, we are only concerned with her vertical motion.
The initial vertical velocity upward is
then we can use the following SUVAT equation:
where
is the final vertical velocity, which is zero at the maximum height
is the initial vertical velocity
h is the maximum height
Solving for h,
B) 1.64 s
The time needed to reach the highest point can be found by analyzing again the vertical motion only. In fact, we can use the following SUVAT equation:
where
At the maximum height, the vertical velocity is zero:
So we can solve the equation to find the corresponding time:
Answer:
m2=3.2722lbm/s
Explanation:
Hello!
To solve this problem follow the steps below
1. Find water densities and entlapies in all states using thermodynamic tables.
note Through laboratory tests, thermodynamic tables were developed, which allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy, etc.)
through prior knowledge of two other properties, such as pressure and temperature.
D1=Density(Water;T=50;x=0) =62.41 lbm/ft^3
D2=Density(Water;T=120;x=0) =61.71 lbm/ft^3
D3=Density(Water;T=80;x=0) =62.21 lbm/ft^3
h1=Enthalpy(Water;T=50;x=0) =18.05 BTU/lbm
h2=Enthalpy(Water;T=120;x=0) =88 BTU/lbm
h3=Enthalpy(Water;T=80;x=0)=48.03 BTU/lbm
2. uses the continuity equation that states that the mass flow that enters a system is the same as the one that must exit
m1+m2=m3
3. uses the first law of thermodynamics that states that all the flow energy entering a system is the same that must come out
m1h1+m2h2=m3h3
18.05(m1)+88(m2)=48.03(m3)
divide both sides of the equation by 48.03
0.376(m1)+1.832(m2)=m3
4. Subtract the equations obtained in steps 3 and 4
m1 + m2 = m3
-
0.376m1 + 1.832(m2) =m3
--------------------------------------------
0.624m1-0.832m2=0
solving for m2
(0.624/0.832)m1=m2
0.75m1=m2
5. Mass flow is the product of density by velocity across the cross-sectional area
m1=(D1)(A)(v1)
internal Diameter for 2" Sch 40=2.067in=0.17225ft
m1=(62.41 lbm/ft^3)(0.0233ft^2)(3ft/S)=4.3629lbm/s
6. use the equation from step 4 to find the mass flow in 2
0.75m1=m2
0.75(4.3629)=m2
m2=3.2722lbm/s
Answer:
Final velocity will be 1.4 m/sec
So option (a) is correct option
Explanation:
We have given there are two acrobats
Mass of first acrobats and its velocity
Mass of second acrobats and its velocity
Now from conservation of momentum we know that
So option (a) is correct option