the I'm pact force of 0.5 is lol u guys go and study why r u asking answers
There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here
You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.
Answer:
d=3.67 m
Explanation:
Height of building=46.0 m
First we need to find time taken by egg to reach 1.80 m above the surface
So to find time use below equation

As velocity 1.20m/s is given and we have find time.So we can easily find the distance
So
The answer is centimeters.
You said 0.5 · m · v² = m · g · h
Divide each side by 'm' : 0.5 · v² = g · h
Multiply each side by 2 : v² = 2 · g · h
Square root each side : v = √(2 · g · h)
You said that g = 9.8 m/s² and h = 875 units
So v = √(9.8 m/s² · 875 units)
v = √(8,575 m·unit/s²)
v = 92.6 / s² · √(m · unit)