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Nonamiya [84]
3 years ago
5

Which of the following does NOT represent a student learning at the rate of 15 vocabulary words in 30 minutes

Mathematics
2 answers:
Paha777 [63]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Maksim231197 [3]3 years ago
4 0

Answer:

D

Step-by-step explanation:

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∠1 = 90°

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FACTOR and list your 4 steps: 5x^2y - 30xy^2
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5x • (x + 3y) • (x - 2y)

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X(x+1)(x+2)(x+3)=24
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Step-by-step explanation:

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2 years ago
What should be your first step when subtracting integers?
iris [78.8K]

Your first step when subtracting integers is (d) subtract the numbers

<h3>How to determine the first step?</h3>

The operation is given as:

Subtraction operation

Assume that the operation is a simple expression that involves subtraction, such as:

a - b

The first step is to subtract the numbers

Hence, your first step when subtracting integers is (d) subtract the numbers

Read more about subtraction at:

brainly.com/question/17301989

#SPJ1

8 0
1 year ago
Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case
olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> =  Mike will show up.

Given:

P(D^{c})=0.55\\P(M^{c})=0.45

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

                                                   =1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0
3 years ago
Read 2 more answers
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