The answer is, "the speed of the current is 5 miles per hour."
To calculate the speed of the current,
let's assume speed of current = xmph. Time taken to travel from one pier to another with the current = 100/(20+x)h
But the time taken to travel from one pier to another with the current, which is given is = 4 hours. So, 4=100/(20+x) 80+4x = 100
4x = 20
x = 5 Thus, the speed of the current is 5 miles per hour.
This method is known as linear perspective.
When using linear perspective, artists use a set of drawn or imaginary lines which are made to converge at the horizon of the image. These lines change the viewer's perspective by providing a point through which the relative size, shape and position of objects is determined. This technique creates the illusion of depth.
Answer:
The cylinder’s total kinetic energy is 1.918 J.
Explanation:
Given that,
Mass = 4.1 kg
Radius = 0.057 m
Speed = 0.79 m/s
We need to calculate the linear kinetic energy
Using formula of linear kinetic energy



We need to calculate the rotational kinetic energy




The total kinetic energy is given by



Hence, The cylinder’s total kinetic energy is 1.918 J.
Answer:
The total work done by Brad each day is 176400 J
Explanation:
Hi there! The work done by a force (F) pointed in the same direction as the displacement (d) is calculated as follows:
W = F · d
The force applied is equal to the weight of Brad, that is calculated as follows:
Weight = m · g
Where:
m = mass of Brad
g = acceleration due to gravity (9.8 m/s²)
Then:
Weight = 60 kg · 9.8 m/s² = 588 N
Let´s find the vertical distance traveled by Brad each day:
He exercises 20 min per day. Each minute Brad does 60 steps. In total, Brad steps up (20 min · 60 steps/min) 1200 steps. If each step has a height of 0.25 m, the total distance traveled by Brad will be
(1200 steps · 0.25 m/step) 300 m.
Then, the total work done by Brad is
W = F · d
W = 588 N · 300 m
W = 176400 J
The total work done by Brad each day is 176400 J
Explanation:
The geometry of the BF 3 molecule is called trigonal planar (see Figure 5). The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.