Answer:
![K_c\text{ = }\frac{[O_2][H_2]\placeholder{⬚}^2}{[H_2O]\placeholder{⬚}^2}](https://tex.z-dn.net/?f=K_c%5Ctext%7B%20%3D%20%7D%5Cfrac%7B%5BO_2%5D%5BH_2%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D%7B%5BH_2O%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D)
Explanation:
Here, we want to write the equilibrium constant expression
To write this, we raise the concentrations of the reactants and products to the coefficient before them. These concentrations are represented by square brackets in which the chemical formula of the compound is placed
We place the representation of the products over that of the reactants
We have the expression written as follows:
The correct answer is c.
answer b is incorrect <span />
Answer:
The density of liquid is 3 g/mL.
The mass of liquid is 60 g.
The volume of liquid is 10 mL.
Explanation:
Given data:
Density of liquid = ?
Mass of liquid = 30 g
Volume of liquid = 10 mL
Solution:
d = m/v
d = density
m = mass
v = volume
Now we will put the values in formula.
d = 30 g/ 10 mL
d = 3 g/mL
The density of liquid is 3 g/mL.
2nd:
Given data:
Density of liquid = 2 g/mL
Volume of liquid = 30 mL
Mass of liquid = ?
Solution:
d = m/v
2 g/mL = m/ 30 mL
m = 2 g/mL×30 mL
m = 60 g
The mass of liquid is 60 g.
3rd:
Given data:
Density of liquid = 5 g/mL
Mass of liquid = 50 g
Volume of liquid = ?
Solution:
d = m/v
5 g/mL = 50 g/ v
v = 50 g/5 g/mL
v = 10 mL
The volume of liquid is 10 mL.
Answer:From 13 moles of CuO 4.3 moles of N₂ are formed
Number of moles of N₂ formed = ?
Number of moles of CuO react = 13 mol
Solution:
Chemical equation:
2NH₃ + 3CuO → 3Cu + N₂ + 3H₂O
Now we will compare the moles of CuO and N₂.
CuO : N₂
3 : 1
13 : 1/3×13 = 4.3 mol
Thus, from 13 moles of CuO 4.3 moles of N₂ are formed.
Explanation:
Well, if the fossil is from the sea/is an ocean animal (for example a fish) , then you can say that the land was once underwater. If the fossil is from a desert, you can say that the land was once a desert, etc.