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kondaur [170]
3 years ago
7

A mineral contains only a metal, M, and sulfur. If analysis indicates that a 44.9 g sample of the mineral contains 2.1 g of M, w

hat mass of M (g) is contained in 329 g of the mineral?
Chemistry
2 answers:
taurus [48]3 years ago
5 0

Answer:

15.38 g is the mass for M in the 329 g of sample

Explanation:

Mineral's formula: MS

Our sample weighs 44.9 g

Mass of M: 2.1 g

Our new sample weighs 329 g

We may solve this by a rule of three:

44.9 g of sample contain 2.1 g of M

329 g of sample will contain (329 . 2.1) / 44.9 = 15.38 g

Inessa [10]3 years ago
3 0

Answer:

In a 329 grams mineral, we have 15.4 grams of metal M

Explanation:

Step 1: Data given

Mass of the sample = 44.9 grams

The mineral contains: 2.1 grams of M

Step 2: Calculate mass % of M

mass % of M = (mass M / total mass sample) * 100 %

mass % of M = (2.1 grams / 44.9 grams) *100 %

mass % of M = 4.677 %

Step 3: Calculate the mass of M in a 329 grams

Mass % = (4.677 grams / 100 % ) * 329 grams

Mass % = 0.04677 * 329 grams

Mass % =  15.4 grams

In a 329 grams mineral, we have 15.4 grams of metal M

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aliina [53]
You need a control so you have something to compare the experimental group on-- If you don't have a control group, how will you know what's changed?
5 0
3 years ago
A tank at is filled with of dinitrogen difluoride gas and of chlorine pentafluoride gas. You can assume both gases behave as ide
jenyasd209 [6]

The question is incomplete, the complete question is;

A 8.00 L tank at 2.64 °C is filled with 9.82 g of chlorine pentafluoride gas and 10.1 g of dinitrogen difluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. Be sure your answers have the correct number of significant digits.

Answer:

See explanation for details

Explanation:

Number of moles of N2F2 = mass/ molar mass

Molar mass of N2F2 = 66 g/mol

Number of moles = 10.1 g/66 = 0.15 moles

Number of moles of ClF5 = 9.82 g/130 g/mol= 0.08 moles

Molar mass of ClF5= 130g/mol

Total number of moles = 0.15 moles + 0.08 moles = 0.23 moles

Given that;

T= 2.64 °C + 273 = 275.64 K

n= 0.23 moles

R= 0.082 Latmmol-1K-1

V= 8.00 L

P= ??

From;

PV =nRT

P= nRT/V

P= 0.23 ×0.082 × 275.64/8.00

P= 0.65 atm

Mole fraction of N2F2= 0.15/0.23 = 0.65

Partial pressure = mole fraction × total pressure = 0.65 × 0.65 = 0.42 atm

Mole fraction of ClF5 = 0.08/0.23 = 0.35

Partial pressure of ClF5 = mole fraction × total pressure = 0.35 × 0.65 = 0.22 atm

6 0
3 years ago
8. What was the original concentration in the BHL sample, if the dilution is 1:500 and the concentration 0.07 mg/ml
Yakvenalex [24]

Answer:

The original concentration is "35 mg/ml".

Explanation:

According to the question,

The solution is diluted,

= 1:50

The initial volume,

V1 = 1 ml

Final concentration,

= 0.07 mg

then,

The final volume,

V2 = 500 ml

As we know,

⇒ V_1N_1=V_2N_2

or,

⇒ N_1=\frac{V_2N_2}{V_1}

On substituting the values, we get

⇒       =\frac{500\times 0.07}{1}

⇒       =\frac{35}{1}

⇒       =35 \ mg/ml

4 0
2 years ago
Select the correct answer. which substance in this redox reaction is the oxidizing agent? cu 2agno3 → 2ag cu(no3)2 a. n b. agno3
lana66690 [7]

AgNO₃ will act as the oxidising agent.

<h3><u>For the given chemical equation:</u></h3>

Cu + 2AgNO₃ →  2Ag + Cu(NO₃)₂

Half reactions for the given chemical reaction:

<u>Reducing agent:</u>

Cu → Cu²⁺ + 2e⁻

Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.

<u>Oxidising Agent</u>:

Ag⁺ + e⁻ → Ag

The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.

Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.

<h3><u>Oxidising and Reducing agents</u></h3>
  • An oxidizing agent is a substance that reduces itself after oxidizing another material. It passes through a reduction process in which it obtains electrons and the substance's oxidation state is decreased.
  • A reducing agent is a chemical that oxidizes after reducing another material. It passes through an oxidation process in which it loses electrons and the substance's oxidation state increases.

To know more about the process of Oxidation and Reduction, refer to:

brainly.com/question/4222605

#SPJ4

8 0
1 year ago
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
viva [34]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

6 0
3 years ago
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