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skelet666 [1.2K]
3 years ago
9

Lance armstrong biking over 40 miles in one day would be considered muscular strength. true or false

Physics
1 answer:
Sonja [21]3 years ago
4 0

True.

Reason:

Muscular strength is the maximum force exerted by a muscle against some form of resistance.

In this example, lance Armstrong is continuously working against the gravitational force. Thus, it can be considered as muscular strength.

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When t= 1 a stone B is thrown vertically upwards from ground level with speed 5ms (ii) find t when a and b collide
Ksju [112]

Answer:

i don't know if this is good for you but

Explanation:

ignoring frictional air resistance (drag) the speed on return is the same as when it left the ground (5 m/s but in the opposite direction).

Note: this points out a good reason for not firing live bullets into the air..they will return somewhere and at the same speed.

However, if you take into account the atmospheric drag the reurn speed will be somewhat smaller (but in the case of a bullet, probably still lethal.) Drag depends on many factors and is difficult to calculate.

5 0
3 years ago
In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin
GuDViN [60]

Answer:

The velocity is v_b = 20.17 \ m/s

Explanation:

From the question we are told that

   The mass of the ball is  m = 0.245 \ kg

   The radius is  r =  59.8 \  cm  =  0.598 \ m

   The force is  F =  30.9 \ N

   The speed of the ball is  v = 16.0 \ m/s.

Generally the kinetic energy at the top of the circle is mathematically represented as

    K_t  =  \frac{1}{2} *  m  *  v^2

=> K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2  

=> K_t  =  31.36 \ J  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       W =  F *  d

Here  d is the length of  a semi - circular arc which is mathematically represented as

       d =  \pi * r

So

      W =  30.9 *  0.598

      W = 18.48 \ J

Generally the kinetic energy at the bottom is mathematically represented as

      K_b  =  \frac{1}{2} *  m *  v_b^2

=>    K_b  =  \frac{1}{2} *  0.245  *  v_b^2

=>   K_b  =  0.1225  *  v_b^2

From the law of energy conservation

     K_t +  W  =K_b

=>    31.36+  18.48 = 0.1225  *  v_b^2

=>    v_b = 20.17 \ m/s

3 0
3 years ago
The mass of the Earth is about 6 x 1024 kg
tia_tia [17]

Well it seems that you did not give answer choices, but that its fine since we can use newtons law of universal gravitational, Fg = GM1M2/r^2. So G is the gravitational constant, which is 6.67*10^-11, we can plug in 6*1024 for M1, and 7*1022 for M2, and 3.8*108 for r. Which then we get 1.74 * 10^8 N as the force of attraction between the Earth and the moon.

3 0
3 years ago
a lamp rated 100w 220 v is connected to mains electric supply . what current is drawn from the supplyy line, if the voltage is 2
melomori [17]
Power = (voltage) x (current)

100w = 220v x current

Current = 100w / 220v = <u>0.455 Ampere</u> (rounded)
5 0
3 years ago
A rock is thrown downward at a speed of 8.5 m/s and hits the ground 2.25 seconds later. From what height was the rock thrown? Wh
vekshin1

Answer:

The velocity and height is 31 m/s and 44.4 m respectively .

Explanation:

Given :

Initial speed of rock , u = 8.5 m/s .

Time taken to reach ground , t = 2.25 s .

Also , acceleration due to gravity is , g=10\ m/s^2 .

Now , to find the velocity when it hit ground .

Applying equation of motion :

v=u+at\\v=8.5+10\times 2.25\\v=31\ m/s

Also , height from which rock is thrown is given by :

h=ut+\dfrac{at^2}{2}\\\\h=8.5\times 2.25+\dfrac{10\times 2.25^2}{2}\\\\h=44.4\ m

Hence , this is the required solution .

7 0
3 years ago
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