A 10.0 kg Fish swimming at 5.0 m/s to the right catches a smaller 2.0 kg fish swimming at 6.0 m/s to the left. When the larger f
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The position of an oscillating mass is given by:
where A is the amplitude of the oscillation, the angular frequency and t the time.
The velocity of the oscillating mass can be found by calculating the derivative of the position:
In this problem, A=2.0 cm and , so if we substitute these data and t=0.4 s we can find the velocity at t=0.4 s:
Answer:
Explanation:
mass per unit length ρ = .100 / 1.65 = .0606 . kg /m
length of wire L = 1.65 m
For fundamental frequency , the expression is as follows
n =
L = 1.65 , T = 16 n and m = .0606
n =
= 4.9 /s .
This is fundamental frequency .
other mode of vibration ( first three ) will be as follows
4.9 x 2 = 9.8 /s ,
4.9 x 3 = 14.7 /s .