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3 years ago

How does Gas Trapping bottles Monitor Volcanos?

1 answer:

4 0

Answer: the pressure releases gas. The two most abundant gases are sulfur dioxide and carbon dioxide, and if levels of these gases increase,

Explanation:

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Ms. Johnson tells the students to make sure they bring their jackets to school tomorrow. She knows that there will be a front of

sladkih [1.3K]

Their path fluctuates to the north or south depending on the location of hot and cold air masses

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2 years ago

Calculate the ph at the equivalence point for the titration of 0.230 m methylamine (ch3nh2) with 0.230 m hcl. the kb of methylam

Vlad1618 [11]

Answer: The pH at the equivalence point for the titration will be 0.65.

Solution:

Let the concentration of $[OH^-]$ be x

Initial concentration of $[CH3NH_2]$ , c = 0.230 M

$CH_3NH_2+H_2O\rightleftharpoons CH_3NH_3^++OH^-$

at eq'm c-x x x

Expression of $K_b$ :

$K_b=\frac{[CH_3NH_3^+][+OH^-]}{[CH_3NH_2]}=\frac{x\times x}{c-x}=\frac{x^2}{c-x}$

Since ,methyl-amine is a weak base,c>>x so $c-x\approx c$ .

$K_b=\frac{x^2}{c}=5.0\times 10^{-4}=\frac{x^2}{0.230 M}$

Solving for x, we get:

$x=1.07\times 10^{-2} M$

Given, HCl with 0.230 M , it dissociates fully in water which means $[H^+]$ = 0.230 M

$[OH^-]=[H^+]$ will result in neutral solution, since $[OH^-]$

Remaining $[H^+]$ after neutralizing $[OH^-]$ ions

$[H^+]_{\text{left in solution}}=[H^+]-[OH^-]=0.230-1.07\times 10^{-2}=0.2193 M$

$pH=-log{[H^+]_{\text{left in solution}}=-log(0.2193)=0.65$

The pH at the equivalence point for the titration will be 0.65.

8 0

4 years ago

Calculate the density of an object with a mass of 3.8 g, that when placed in a 10.0 mL graduated cylinder with an initial volume

Arturiano [62]

Answer : The density of an object is 0.93 g/mL

Explanation : Given,

Mass of an object = 3.8 g

Initial volume = 4.5 mL

Final volume = 8.6 mL

First we have to calculate the volume of an object.

Volume of an object = Final volume - Initial volume

Volume of an object = 8.6 mL - 4.5 mL

Volume of an object = 4.1 mL

Now we have to calculate the density of an object.

Formula used:

$\text{Density}=\frac{\text{Mass of an object}}{\text{Volume of an object}}$

Now putting all the given values in this formula, we get:

$\text{Density}=\frac{3.8g}{4.1mL}$

$\text{Density}=0.93g/mL$

Therefore, the density of an object is 0.93 g/mL

3 0

3 years ago

How many molecules of lactate can one molecule of lactate dehydrogenase act on in 21 minutes?

USPshnik [31]

The turnover number (number of molecules the enzyme can act on per second) for lactase dehydrogenase is 1,000 lactate molecules per second.
In one minute, this becomes:

(1,000 molecules / second) * (60 seconds / minute)
= 60,000 molecules / minute

In 21 minutes, this will be:

60,000 * 21

= 1.26 x 10⁶ molecules of lactate

6 0

4 years ago

Describe a plant or animal that lives in the water and how it uses the water to survive.

Alina [70]

Answer:

A great example would be a fish, it needs the water to breathe just like how we humans need oxygen. If a fish were to get out of the water it would die.

Explanation:

4 0

3 years ago