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3 years ago

Physical properties can be observed

Chemistry

2 answers:

Alika [10]3 years ago

4 0

Answer:

Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others. That is your answer! Thanks! :)

Explanation:

Harrizon [31]3 years ago

4 0

B: Composition

Explanation: Physical properties can be observed or measured without changing the composition of matter.

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What is used to contain an acid spill and what are the characteristics of them?

Bingel [31]

Is that chemistry?
Cause I'm kinda confused about how to help you with this question

6 0

2 years ago

How many moles of AlCl3 are formed by 1.53 moles of CuCl2?

jolli1 [7]

Answer:

1.02 moles of AlCl3

Explanation:

Consider the balanced reaction equation shown below;

2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)

This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.

Given that;

3 moles of CuCl2 yields 2 moles of AlCl3

1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3

5 0

2 years ago

Son el punto 2,3,4 por favor

RSB [31]

4...........................

8 0

3 years ago

1. A physician ordered 2.0 milligrams tetracycline to be given to a patient. If the tetracycline was available as 0.75 mg/mL of

Cerrena [4.2K]

Answer:

2.67 mL

Explanation:

The following data were obtained from the question:

Mass of tetracycline = 2 mg

Density of tetracycline = 0.75 mg/mL

Volume of tetracycline =?

We can obtain the volume of the tetracycline that should be given to the patient by applying the following equation:

Density = mass /volume

0.75 = 2 / volume

Cross multiply

0.75 × Volume = 2

Divide both side by 0.75

Volume = 2/0.75

Volume = 2.67 mL

Therefore, the volume of the tetracycline that should be given to the patient is 2.67 mL

6 0

3 years ago

Arterial blood contains about 0.25 g of oxygen per liter at 37°C and standard atmospheric pressure. Under these conditions, the

Olin [163]

Firstly we need to determine the partial pressure of O2:

$\begin{gathered} P_{O_2}=X\times P_T \\ P_{O_2}:partial\text{ }pressure \\ X:mole\text{ }fraction \\ P_T:total\text{ }pressure \\ \\ P_{O_2}=0.209\times0.35\text{ }atm \\ P_{O_2}=0.073\text{ }atm \end{gathered}$

We will now use the Henry's Law equation to determine the solubility of the gas:

$\begin{gathered} c=K_H\times P_{O_2} \\ c:solubility\text{ }or\text{ }concentration\text{ }of\text{ }the\text{ }gas(M) \\ K_H:Henry^{\prime}sLawconstant=3.7\times10^{-2}M\text{ }atm^{-1} \\ P_{O_2}:partial\text{ }pressure\text{ }of\text{ }the\text{ }gas=0.073atm \\ \\ c=3.7\times10^{-2}M\text{ }atm^{-1}\times0.073 \\ c=2.7\times10^{-3}M \end{gathered}$

Answer: Solubility is 2.7x10^-3 M

6 0

10 months ago