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Zolol [24]
3 years ago
8

The pipet used for transferring the pickle juice to the flask was dirty and consequentially some of the pickle juice stuck to th

e inside of the pipet and was not analyzed. Would the determined percentage of acetic acid in the food sample be higher or lower due to this error? Explain your answer.
Chemistry
1 answer:
lesya [120]3 years ago
6 0

Explanation:

Since, some of the given sample is stuck inside and behind the pipet. Hence, there will occur a decrease in the percent of acetic acid.

This is because a decrease in concentration of the acid will also lead to a decrease in the amount of sample taken for the estimation. Since. lesser is the amount or concentration present lesser will be its analyte concentration.

For example, we took 10 mg of a pickel sample but 3 mg of the sample remain stuck in the pipet. This means we actually titrating a  sample less than 10 mg.

Therefore, the analyte concentration in the pickel will also be less.

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The molar mass of a certain gas is 80.6 g. What is the density of the gas in g/L at STP?
vfiekz [6]
Using the ideal gas equation:
PV = nRT

Substituting n with mass / Mr
PV = mRT/Mr

Density = m/V
So rearranging:
Density = PMr/RT

P = 1 atm
R = 0.082 L atm / K mol
T = 273 K
Density = (1 x 80.6) / (0.082 x 273)
Density = 3.6 g / L
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3 years ago
I need help with this question ASAP
avanturin [10]

Answer:

True

Explanation:

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Which of the following best describes how further studies supported the work done by Max Planck in the field of quantum mechanic
givi [52]

Answer:

Neils Bohr determined that electrons inhabit distinct energy levels.

Explanation:

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3 years ago
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Why is it important to control all of the variables except one in an experiment?
Ad libitum [116K]
Any given experiment has numerous control variables, and it's important for a scientist to try to hold all variables constant except for the independent variable. If a control variable changes during an experiment, it may invalidate the correlation between the dependent and independent variables.



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5 0
3 years ago
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Urea, CH4N2O (s), is manufactured from NH3 (g) and CO2 (g). H2O (l) is another product of this reaction. An experiment is starte
Katarina [22]

Answer:

a. 4.41 g of Urea

b. 1.5 g of Urea

Explanation:

To start the problem, we define the reaction:

2NH₃ (g) +  CO₂ (g) → CH₄N₂O (s)  +  H₂O(l)

We only have mass of ammonia, so we assume the carbon dioxide is in excess and ammonia is the limiting reactant:

2.6 g . 1mol / 17g = 0.153 moles of ammonia

Ratio is 2:1. 2 moles of ammonia can produce 1 mol of urea

0.153 moles ammonia may produce, the half of moles

0153 /2 = 0.076 moles of urea

To state the theoretical yield we convert moles to mass:

0.076 mol . 58 g/mol = 4.41 g

That's the 100 % yield reaction

If the percent yield, was 34%:

4.41 g . 0.34 = 1.50 g of urea were produced.

Formula is (Yield produced / Theoretical yield) . 100 → Percent yield

3 0
3 years ago
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