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zheka24 [161]
3 years ago
12

Someone plz help me :(

Chemistry
1 answer:
sleet_krkn [62]3 years ago
6 0

c.

Explanation:

I mainly think its c. from my point of view because as yoy can see they showed observations and explained certain information and they didnt conclude it as it's TRUE they said theories meaning its and Idea and something that is not fully proven happend.

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What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?
Lerok [7]

Answer:

2.68 Liters

Explanation:

ideal gas law

PV=NRT

to get the volume

rearrange the formula

V=nRT/P

R molar gas constant is in units joules per mole kelvin :

8.314 J/(mol K) (joules per mole kelvin)

T temperature part of this is in kelvin so you have to convert the Celsius temperature to kelvin

1 Celsius is 274.15 kelvin so

83.4 Celsius is 356.55 kelvin

P pressure is in Pascal or Pa units

so you have to convert atm into Pa

1 atm is 201636.8 Pa or Pascals so

1.99 atm is 201636.8 Pa

V volume will be in cubic meters or m^3

m^3 will need to changed to liters

1 cubic meter or m^3 is 1000 liters

n amount of substance is in moles

again the rearranged formula is

V=nRT/P

(0.182*8.314*356.55)/201636.8 =

0.00267566693 cubic meters or m^3

1 cubic meter or m^3 is 1000 liters so

0.00267566693 cubic meters or m^3 times 1000 =

2.67566693 liters

4 0
2 years ago
A compound contains 74.2 g Na and 25.8 g O. Determine the Empirical Formula for this compound
Ksenya-84 [330]

Answer:

The empirical formula for the compound is Na2O

Explanation:

Data obtained from the question include:

Sodium (Na) = 74.2g

Oxygen (O) = 25.8g

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First, divide the above by their individual molar mass as shown below:

Na = 74.2/23 = 3.226

O = 25.8/16 = 1.613

Next, divide the above by the smallest number

Na = 3.226/1.613 = 2

O = 1.613/1.613 = 1

Therefore, the empirical formula is:

Na2O

4 0
3 years ago
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Answer:

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Explanation:

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6 0
3 years ago
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777dan777 [17]
Answer: C excess reactant

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